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Tomtit [17]
3 years ago
5

I am a 7 digit even number the sum of my digits is 23 .My largest digit is in the hundreds place my smollest digit is in the ten

s place . My millions and tens thousands digits are the same the hundreds place is my only composit number .What number am i?
Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0

Answer:

There are two possibilities for the number. They are 3531902 and 3135902

Step-by-step explanation:

(i) Given that the sum of the digits = 23

(ii) Largest digit is in the hundreds place (5th digit)

(iii) Smollest digit is in the tens place (6th digit)

(iv) Millions and tens thousands digits are the same, (1st and 3rd digit)

(v) Hundreds place is my only composit number(5th digit)

The composite numbers < 10 are 4, 6, 8, 9

(vi) Since the number is an even number, the 7th digit must be either 0,2,4,6,8.

It cannot be 4,6,8 due to case (v) and it cannot be 0 due to case (iii), hence 7th digit is 2 and the 6th digit has to be 0.

(vii) 5th digit has to be either 6,8 or 9, and by making it as 6 or 8, there are less options and it doesn't satisfy other conditions and so 9 is the 5th digit.

The 1 - 4 digits has to be filled by 1,3,5,7. By probability and case (i), there are 2 combinations, they are 3531902 and 3135902.

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