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slega [8]
2 years ago
5

Help! me find perimeter for kite help check

Mathematics
2 answers:
ozzi2 years ago
5 0

√(58)*2 + √(25)*2

answer: 2√58+10

Aleks [24]2 years ago
5 0

Answer:

10 + 2\sqrt{58}

Step-by-step explanation:

perimeter of DEFG = DE + EF + FG + DG

DE, EF, FG, and DG are all hypotenuse.

DE =\sqrt[]{4^{2} + 3^{2} }  = 5

EF = \sqrt{4^{2}+3^{2}  } = 5

FG = \sqrt{3^{2} +7^{2} } = \sqrt{58}

DG = \sqrt{3^{2}+7^{2}  } = \sqrt{58}

DE + EF + FG + DG

= 5 + 5 + \sqrt{58} + \sqrt{58}

= 10 + 2\sqrt{58}

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Wewaii [24]
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38 - 7r = 18 - 12r
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3 years ago
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Your answer A12/A6= A6
4 0
2 years ago
The area of the trapezium is 63cm and the top is 6cm and the bottom is 12cm what’s the height
steposvetlana [31]

Answer:

height = 7 cm

Step-by-step explanation:

The area (A) of a trapezium is calculated using the formula

A = \frac{1}{2} h(a + b)

where h is the height and a, b the parallel bases

here a = 6, b = 12 and A = 63, hence

\frac{1}{2} × h × (6 + 12) = 63

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7 0
3 years ago
Angle Relationships
KonstantinChe [14]

Answer:

D. 21 m

Step-by-step explanation:

I calculated it logically

8 0
3 years ago
cho tứ giác ABCD. Gọi M,N,P,Q là trung điểm của các cạnh AB, CD, AD, BC. Chứng minh rằng vecto MP = vecto QN, vecto MQ = vecto P
Dmitriy789 [7]

Answer:

Step-by-step explanation:

Xét tam giác DAB có: P là trung điểm AD, M là trung điểm AB

=> MP là đường trung bình của tam giác DAB => MP//BD và MP=\frac{1}{2}BD  (1)

Xét tam giác DBC có: N là trung điểm DC, Q là trung điểm BC

=> QN là đường trung bình của tam giác DBC => QN//BD và QN=\frac{1}{2}BD  (2)

Từ (1) và (2) => vecto MP song song cùng chiều với vecto QN

và độ dài MP = độ dài QN = \frac{1}{2}BD

=> vecto MP = vecto QN

Tương tự xét các tam giác DAC và tam giác ABC => vecto MQ = vecto PN

4 0
3 years ago
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