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slega [8]
2 years ago
5

Help! me find perimeter for kite help check

Mathematics
2 answers:
ozzi2 years ago
5 0

√(58)*2 + √(25)*2

answer: 2√58+10

Aleks [24]2 years ago
5 0

Answer:

10 + 2\sqrt{58}

Step-by-step explanation:

perimeter of DEFG = DE + EF + FG + DG

DE, EF, FG, and DG are all hypotenuse.

DE =\sqrt[]{4^{2} + 3^{2} }  = 5

EF = \sqrt{4^{2}+3^{2}  } = 5

FG = \sqrt{3^{2} +7^{2} } = \sqrt{58}

DG = \sqrt{3^{2}+7^{2}  } = \sqrt{58}

DE + EF + FG + DG

= 5 + 5 + \sqrt{58} + \sqrt{58}

= 10 + 2\sqrt{58}

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6.9 ×10^-2

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The standard form 0. 00293768 is
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What’s the answer to this problem?
Alja [10]

Answer:

Figure:         Amount of tiles:

1                    5

2                   8

3                   11

4                   14

5                   17

6                   20

7                   23

8                   26

9                   29

10                 32

11                  35

12                 38

13                 41

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3 0
3 years ago
Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

6 0
3 years ago
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