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Elanso [62]
3 years ago
8

A black guinea pig crossed with an albino guinea pig produced twelve black offspring. when the albino was crossed with a second

black animal, six blacks and six albinos were obtained. what is the best explanation for this genetic situation?
Biology
1 answer:
Firdavs [7]3 years ago
6 0
I think the best explanation for this genetic situation would be that Albino is recessive and black is dominant. In genetics, a trait that will appear in the offspring if one of the parents contributes it. The relationship between alleles of one gene, in which the effect on phenotype of one allele masks the contribution of a second allele at the same locus. The first allele is dominant and the second allele is recessive. In this case the black color is dominant over the albino trait.
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16/64 = 1/4

Explanation:

This is a typical trihybrid cross involving three genes T, P and Y. A plant with genotype TTPpYy is crossed with a plant recessive for all traits (ttppyy).

According to Mendel's law of independent assortment, each allele for each gene will get sorted into the following 8 gametes with only 4 different: TPY, TPy, TpY, Tpy, TPY, TPy, TpY and Tpy.

The recessive parent, ttppyy will produce tpy, tpy, tpy, tpy, tpy, tpy, tpy and tpy.

Hence, using a punnet square, 64 offsprings will be produced with only 16 of them heterozygous dominant for the three traits with genotype (TtPpYy). Hence, proportion is 16/64 equivalent to 1/4.

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