Answer:
Sh. 300,001.60
Explanation:
Note: <em>Missing word has been attached</em>
Particulars Amount
Annual payments 86,038
x PV Annuity due 8%, 10 periods 3.48685
Amount recorded for the leased asset 300,001.60
Answer:
When Manufacturing of a Product involves several processes.
Explanation:
When several processes are involved in manufacturing a product, costs need to be accumulated in these processing departments. Thus, A process cost accounting system is most appropriate
Answer:
Present value = $21,804 (approx)
Explanation:
Given:
Periodic payment = $3,200
Number of period = 12
Interest rate = 10% = 10/100 = 0.1
Present value = ?
Computation of Present value:
![Present\ value = PMT[\frac{1-(1+r)^{-n}}{r} ]\\\\Present\ value = 3,200[\frac{1-(1+0.1)^{-12}}{0.1} ]\\\\Present\ value = 3,200[\frac{1-(1.1)^{-12}}{0.1} ]\\\\Present\ value = 3,200[\frac{1-0.318630818}{0.1} ]\\\\Present\ value = 3,200[\frac{0.681369182}{0.1} ]\\\\Present\ value = 21,803.6188](https://tex.z-dn.net/?f=Present%5C%20value%20%3D%20PMT%5B%5Cfrac%7B1-%281%2Br%29%5E%7B-n%7D%7D%7Br%7D%20%5D%5C%5C%5C%5CPresent%5C%20value%20%3D%203%2C200%5B%5Cfrac%7B1-%281%2B0.1%29%5E%7B-12%7D%7D%7B0.1%7D%20%5D%5C%5C%5C%5CPresent%5C%20value%20%3D%203%2C200%5B%5Cfrac%7B1-%281.1%29%5E%7B-12%7D%7D%7B0.1%7D%20%5D%5C%5C%5C%5CPresent%5C%20value%20%3D%203%2C200%5B%5Cfrac%7B1-0.318630818%7D%7B0.1%7D%20%5D%5C%5C%5C%5CPresent%5C%20value%20%3D%203%2C200%5B%5Cfrac%7B0.681369182%7D%7B0.1%7D%20%5D%5C%5C%5C%5CPresent%5C%20value%20%3D%2021%2C803.6188)
Present value = $21,804 (approx)
First, you have to calculate the amount of tuition when the student reaches age 18. Do this by multiplying $11,000 by 1.07 each year from age 12 until it reaches age 18. Thus, 7 times.
At age 18: 16,508
At age 19: 17,664
At age 20: 18,900
At age 21: 20,223
Then, we use this formula:
A = F { i/{[(1+i)^n] - 1}}
where A is the monthly deposit each year, F is the half amount of the tuition each year illustrated in the first part of this solution, n is the number of years lapsed.
At age 18:
A = (16508/2) { 0.04/{[(1+0.04)^6] - 1}} = $1,244.389 deposit for the 1st year
Ate age 19
A = (17664/2) { 0.04/{[(1+0.04)^7] = $1,118 deposit for the 2nd year
At age 20:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $1,025 deposit for the 3rd year
At age 21:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $955 deposit for the 4th year
Answer:
I have solved part a) because question contains only part a) however it has 3 more parts as well but that are not mentioned in the question. Part a) is explained below.
Explanation:
a) The distribution should be right skewed as most of the numbers lies at that side while using the median to correctly represent an observation in the distribution.
To represent the variability of the observations, interquartile range could be used. Since, there is a good number of expensive houses and this would increase the mean and standard deviation. So, it is better to use interquartile range to represent it, i.e. upper quartile for expensive houses, and lower quartile for less expensive houses and middle quartile for mid-range priced houses.
