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Alenkinab [10]
3 years ago
13

Adding polynomials?? Your answer should be an expanded polynomial in standard form.

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

Answer:

-4b^3 + b^2

Step-by-step explanation:

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Lisa typed a 165-word paragraph in three minutes. Use the ratio table to
JulsSmile [24]

Answer:

1 minute

Step-by-step explanation:

We can see that Lisa types 165 words in 3 mins.

So she types 55 words in 1 minute.

How did I work that out?

Well, all you really do is \frac {165}{3} which is equal to \frac{55}{1} if you divide top and bottom by 3. Anything divided by 1 is itself.

8 0
2 years ago
Can someone help, please
Jet001 [13]

Answer: 5/1 or just 5

Step-by-step explanation:

6 0
1 year ago
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Find the cost per ounce of a gold alloy made from 30 oz of pure gold that costs $1290 per ounce and 60 oz of an alloy that costs
Romashka [77]
The answer would be $24.55 per oz of gold alloy so rounded up would be $25
6 0
3 years ago
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Emilio bought an ant farm that had 15 ants in it already. He read somewhere that
Nina [5.8K]

The number of ants in his farm after 12 weeks is 218.

Step-by-step explanation:

Step 1:

It is given that there are 15 ants initially and the ant population increases by 25% each week.

This is an exponential rate of increase that can be modeled by the following equation:

Number of ants after n weeks = Initial number of ants * (1 + rate of increase) ^{n}

Step 2:

Rate of increase = 25% = 25 / 100 = 0.25

Number of weeks = 12

Number of ants  after 12 weeks = 15* (1 + 0.25 )^{12} = 218.27 (rounded off to 218)

Step 3:

Answer:

The number of ants in his farm after 12 weeks is 218.

6 0
3 years ago
Sid is packing crushed ice into a cone-shaped cThe cone has a height of 5 in. Its base has a diameter of 4 in. What is thevolume
bagirrra123 [75]
The\ volume\ of\ the\ cone:V=\dfrac{1}{3}\pi r^2H\\\\H=5\ in\\2r=4\ in\to r=2\ in\\\\subtitute\\\\V=\dfrac{1}{3}\pi\cdot2^2\cdot5=\dfrac{1}{3}\pi\cdot4\cdot5=\dfrac{20}{3}\pi\ (in^3)\\\\Answer:\boxed{V=\dfrac{20}{3}\pi\ in^3}
7 0
3 years ago
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