Answer: 4(x +1)
You get that answer because first you subtract the numbers and find your common factor so the answer is 4(x + 1)
For this problem, all you need to do is find the three #'s that add up to 156.
So, lets look at the answers and add them up.
A. 50, 52, 54
50 + 52 + 54 = 156
B. 51,52,53
51 + 52 + 53 = 156
C. 49,50,51
49 + 50 + 51 = 150
D. 49,51,53
49 + 51 + 53 = 153
We get the answers (50,52,54) and (51,52,53)
Now, consecutive numbers are numbers that in order, like 1,2,3.
Therefore, the answer is (51,52,53)
The usual definition of Least Common Multiple of two numbers states that is the Least positive integer that can be evenly divided by both numbers. The way it is usually defined the two numbers must be positive integers
Given a Venn diagram showing the number of students that like blue uniform only as 32, the number of students that like gold uniform only as 25, the number of students that like blue and gold uniforms as 12 and the number of students that like neither blue nor gold uniform as 6.
Thus, the total number of students interviewed is 75.
Recall that relative frequency of an event is the outcome of the event divided by the total possible outcome of the experiment.
From the relative frequency table, a represent the relative frequency of the students that like gold but not blue.
From the Venn, diagram, the number of students that like gold uniform only as 25, thus the relative frequency of the students that like gold but not blue is given by

Therefore,
a = 33% to the nearest percent.
Similarly, from the relative frequency table, b represent the relative frequency of the students that like blue but not gold.
From
the Venn, diagram, the number of students that like blue uniform only
as 32, thus the relative frequency of the students that like gold but
not blue is given by

Therefore,
b = 43% to the nearest percent.
Answer:
im pretty sure it would be 15%
Step-by-step explanation:
so A