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3 years ago

Pleaseee helppppppppppppppppppp

Mathematics

1 answer:

quester [9]3 years ago

7 0

To find Angle A we use cosine

cos ∅ = adjacent / hypotenuse

From the question

The adjacent is 17

The hypotenuse is 38

So we have

cos A = 17/38

A = cos-¹ 17/38

A = 63.4

<h3>A = 63° to the nearest degree</h3>

To find Angle C we use sine

sin ∅ = opposite / hypotenuse

From the question

The opposite is 17

The hypotenuse is 38

So we have

sin C = 17/38

C = sin-¹ 17/38

C = 26.57

<h3>C = 27° to the nearest degree</h3>

Hope this helps you

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Sushil was thinking of a number. Sushil doubles it, then adds 20 to get an answer of 25.7. What was the original number?

vredina [299]

Answer:

2.85

Step-by-step explanation:

2x+20=25.7

2x+20-20=25.7-20

2x=5.7

2x/2=5.7/2

x=2.85

8 0

3 years ago

Anna charges $8.50 an hour to babysit how long will it take to make $51.00

kogti [31]

Answer:

6 hours

Step-by-step explanation:

$51.00 ÷ $8.50 = 6 hours

hope this helps ! :))

6 0

3 years ago

5. Landon bought a new car for $16,000 and it depreciates 4.5% every year. Write a function that describes

snow_tiger [21]

Answer:

<h3>The value C(t) of the car after 5 years is $12709.</h3>

Step-by-step explanation:

Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.

<h3>To find the value C(t) of the car after 5 years:</h3>

Initial value $C(0)= $16,000$

Depreciation rate is $r=\frac{4.5}{100}$

Period , t=5 years

$C(t)=C(0)(1-r)^t$

Substitute the values we get

$C(5)=16000(1-0.045)^5$

$=16000(0.955)^5$

$=16000(0.7943)$

∴ $C(5)=12708.8$

<h3>The value C(t) of the car after 5 years is $ 12709</h3>

3 0

3 years ago

Dewmini has two coconuts lands as A and B. A seller ask to have one coconut at Rs. 34. But Dewmini got Rs. 25 000 income by sell

Musya8 [376]

$\textsf{\qquad\qquad\huge\underline{{\sf Answer}}}$

Volume of a rectangular prism is ~

$\sf{Volume_{cuboid}= Length × Width × Height}$

$\qquad \sf \dashrightarrow \: v = (4x + 2) \times (3x - 5) \times (7x + 4)$

$\qquad \sf \dashrightarrow \: v = (12 {x}^{2} - 20x + 6x - 10) \times (7x + 4)$

$\qquad \sf \dashrightarrow \: v = (12 {x}^{2} - 14x- 10) \times (7x + 4)$

$\qquad \sf \dashrightarrow \: v = 84 {x}^{3} + 48 {x}^{2} - 98x {}^{2} - 56x - 70x - 40$

$\qquad \sf \dashrightarrow \: v = 84 {x}^{3} - 50 {x}^{2} - 126x - 40$

So, the correct choice is B

6 0

2 years ago

Two parabolas have the same focus, namely the point $(3,-28).$ Their directrices are the $x$-axis and the $y$-axis, respectively

jeyben [28]

Answer:

the slope of the common cord is: $-1$

Step-by-step explanation:

Given the focus (a,b) = (3,-28)

for a parabola with directrix at x-axis the equation will be

$\left(x-a\right)^{2}+\left(y-b\right)^{2}=y^{2}$

$\left(x-a\right)^{2}+\left(y-b\right)^{2}-y^{2}=0$

for a parabola with directrix at y-axis the equation will be

$\left(x-a\right)^{2}+\left(y-b\right)^{2}=x^{2}$

$\left(x-a\right)^{2}+\left(y-b\right)^{2}-x^{2}=0$

The common chord is the line between two points where the two parabolas intersect. For intersection, we can equate the two parabolas!

In other words, at the point of intersection of these two parabolas the values of the two parabolas will be the same.

$\left(x-a\right)^{2}+\left(y-b\right)^{2}-y^{2}=\left(x-a\right)^{2}+\left(y-b\right)^{2}-x^{2}$

$\left(x-3\right)^{2}+\left(y+28\right)^{2}-y^{2}=\left(x-3\right)^{2}+\left(y+28\right)^{2}-x^{2}$

we can now simplify the equation. (we can see that (x-3) and (y+28) both cancel out by -(x-3) and -(y+28))

$-y^{2}=-x^{2}$

$y=\sqrt{x^{2}}$

$y=\pm x$

this the equation of the common cord. but we need to select whether its

$y=+ x$ or $y=-x$ .

This can be found by realizing that the focus lies on the 4th quadrant of the xy-plane! And the equation $y=-x$ also generates a line that exists in the 2nd and 4th quadrant.

Hence the slope of the common cord is the slope of the line $y=-x$

that is : $-1$

3 0

3 years ago