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3 years ago

Pleaseee helppppppppppppppppppp

Mathematics

1 answer:

quester [9]3 years ago

7 0

To find Angle A we use cosine

cos ∅ = adjacent / hypotenuse

From the question

The adjacent is 17

The hypotenuse is 38

So we have

cos A = 17/38

A = cos-¹ 17/38

A = 63.4

<h3>A = 63° to the nearest degree</h3>

To find Angle C we use sine

sin ∅ = opposite / hypotenuse

From the question

The opposite is 17

The hypotenuse is 38

So we have

sin C = 17/38

C = sin-¹ 17/38

C = 26.57

<h3>C = 27° to the nearest degree</h3>

Hope this helps you

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Answer:

Step-by-step explanation:

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3 years ago

Which number do you add to 3 to get 0?

grandymaker [24]

Answer:

-3

Step-by-step explanation:

3 + (-3) = 0

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3 years ago

Read 2 more answers

A student receives test scores of 62, 83, and 91. This student's term project score is 88. Each test is worth 20% of the final g

miskamm [114]

Answer:

The student's current average score will be 69.2

Step-by-step explanation:

Let first test be TEST A: which is 20 of total and secures 62

Let second test be TEST B: which is 20 of the total marks and has secured 83.

Let third test be TEST C: which is 20 of total and has secured 91.

And now the TEST D which is 25 of total and has secured 88.

Therefore, by multipying across

${0.2}\times{62}$ = 12.4

${0.2}\times{83}$ = 16.6

${0.2}\times{91}$ = 18.2

${0.25}\times{88}$ =22

Now, by adding the scores to get the average score

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6 0

3 years ago

Find the value C(-2), where C is defined below.<br> C(x) = -3x2 – 3x - 3

Harman [31]

Answer:

C(-2) = -9

Step-by-step explanation:

Step 1: Define

C(x) = -3x² - 3x - 3

C(-2) = x = -2

Step 2: Substitute and Evaluate

C(-2) = -3(-2)² - 3(-2) - 3

C(-2) = -3(4) + 6 - 3

C(-2) = -12 + 6 - 3

C(-2) = -6 - 3

C(-2) = -9

3 0

3 years ago

A hog producer is feeding soybean meal and corn to his pigs. He needs to know how many pounds he needs to feed of each in order

Mazyrski [523]

Answer:

Feed 1, Soybean meal required = $\dfrac{2000}{3} \text{ lbs.}$

Feed 2, Corn meal required = $\dfrac{4000}{3} \text{ lbs.}$

Step-by-step explanation:

Total feed is <em>1 ton</em> i.e. <em>2000 lbs</em>.

Let <em>x</em> be the amount of Feed 1 required.

Feed 1 has $45\%$ of protein.

$\text{Protein in Feed 1 = }x \times \dfrac{45}{100} ..... (1)$

Then, amount of Feed 2 required = $(2000 - x) \text{ lbs.}$

Feed 2 has $15\%$ of protein.

$\text{Protein in Feed 2 = }(2000 - x) \times \dfrac{15}{100} ..... (2)$

As per question, total protein required is $25\%$ of 2000 lbs .

Adding (1) and (2) and putting it equal to total protein required.

$\Rightarrow x \times \dfrac{45}{100} + (2000 - x) \times \dfrac{15}{100} = 2000 \times \dfrac{25}{100}\\\Rightarrow 45x + 30000 - 15x = 50000\\\Rightarrow 30x = 20000\\\Rightarrow x = \dfrac{2000}{3}$

Feed 1 required = $\dfrac{2000}{3}\text{ lbs .}$

Feed 2 required = $2000 - \dfrac{2000}{3}\\$

$\Rightarrow \dfrac{4000}{3}\text{ lbs.}$

7 0

3 years ago