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Lynna [10]
2 years ago
9

Guys help me please I need this in September 27,2018

Mathematics
1 answer:
Dmitrij [34]2 years ago
5 0
Okay so first off first off I believe 4-6 is linear because it is increasing at a steady rate and 7 is exponential because it has a constant rate of growth. I’m not 100% I’m correct on that. 8 is linear, 9 is exponential.
For 4: f(x)=-1/2x + 1
5: f(x)=-2x +4
That’s all I know right now. I hope it helps a little bit
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9.5000032 is one such number
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3 years ago
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In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

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6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

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7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
3 years ago
If the sum of the measures of the interior angles of a polygon is 1920°, how many sides does it have?
gizmo_the_mogwai [7]

Answer:

<u>The regular polygon has 13 sides</u>

Correct statement and question:

If the sum of the measures of the interior angles of a polygon is 1980°, how many sides does it have?

Source:

1,920° is not a valid value for a regular polygon. It should be either 1,980° or 1,800° (it has to be a multiple of 180). We pick 1,980° to answer the question.

Step-by-step explanation:

Let's recall that the formula of the sum of the interior angles of any polygon is:

Sum of Interior Angles = (n-2) * 180°, where n is the number of sides of the polygon.

Therefore, replacing with the value we know:

1,980 = (n-2) * 180

n - 2 = 1,980/180

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7 0
3 years ago
~*Please help*~ what is x [ 82.24 =- 8.48 + 4x ]
Ivahew [28]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
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aleksley [76]

Answer:

she could by 16 pencils with 20 cents left over

Step-by-step explanation:

so the fraction is 16 and 2/3

so she could buy 16 pencils and have 20 cents leftover

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2 years ago
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