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IrinaK [193]
3 years ago
6

To use the two sample t procedure to perform a significance test on the difference of two means, we assume: a) The populations'

standard deviation are known. b) The samples from each population are independent. c) The sample sizes are large. d) The distributions are exactly normal in each population.
Mathematics
1 answer:
Anika [276]3 years ago
7 0

Answer:

The option which is an exception is;

c) The sample sizes are large

Step-by-step explanation:

Here the requirement to perform a two sample t procedure are as follows;

1. The two samples have equal variance, hence the variance should be known

2. The samples for which the two sample t procedure is performed must be independent

3. The data are in alignment with the normal distribution probability

4. The samples are random samples taken from the different respective population

Since the sample size is known, we do not assume that the sample size are large.

Therefore options a), b) and d) are all correct except option c).

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4 0
2 years ago
I) CD and EF are parallel lines.
Elodia [21]

Answer:

1. J because it's a straight line

2. 225

however I only got 4 marks not 5.

Step-by-step explanation:

4 0
2 years ago
The length of the Earth’s equator is about 40,000 km, and the Earth’s diameter is 8/25 the length of the equator. What is the di
o-na [289]

Answer:

See Below:

Step-by-step explanation:

40,000*8/25= the diameter, because the diameter is 8/25 of the equator which is 40000

Diameter= 40,000*8/25

Diameter= 12,800 km

8 0
3 years ago
Select the best possible first step to solving the system by first eliminating the x variable.
zheka24 [161]
It seems to be none of the above
3 0
3 years ago
Jon recently drove to visit his parents who live 280 miles away. On his way there his average speed was 9 miles per hour faster
Luba_88 [7]

Answer:

11 mph and 20 mph

Step-by-step explanation:

Represent his average speed going by r1 and his average speed returning by r2.  We know that r1 = r2 + 9.

Recall that distance = rate times time, so time = distance / rate.

Time spent going was (280 mi) / r1, or (280 mi) / (r2 + 9 mph).

Time spend returning was (280 mi) / r2.

The total time was 14 hrs, so (280 mi) / (r2 + 9 mph) + (280 mi) / r2 = 14 hrs

Note that there is only one variable here:  r2.  Find r2, and then from r2, find r1:

Dividing all 3 terms by 14 hrs yields:

  20            20

---------- + ----------- = 1

r2 + 9         r2

The LCD here is r2(r2 + 9).  Thus, we have:

      20r2                    (r2 +  9)(r2)

------------------- = 1 or  ------------------

 (r2 +  9)(r2)               (r2 +  9)(r2)

Then 20(r2) = (r2)^2 + 9(r2).  This is reducible by dividing all terms by r2:

20 = r2 + 9, or 11 = r2.  Then r1 = 11 + 9, or 20.

The two rates were 11 mph and 20 mph.

8 0
3 years ago
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