Answer:
27 < 5*n +7
n<4
Step-by-step explanation:
Twenty-seven is smaller than five times a number increased by seven
Increase means add
27 < 5*n +7
Subtract 7 from each side
27-7 <5n+7-7
20 < 5n
Divide by 5
20/5 < 5n/5
4 <n
Answer:
the answer is simply the one in the bottom right, B
Answer:
22
Step-by-step explanation:
12+12=24
46-24=22
Given the table below representing the number of hours of television nine Math II class students watched the night before a big test on
triangles
along with the grades they each earned on that test.
![\begin{center} \begin{tabular} {|c|c|} Hours Spent Watching TV & Grade on Test (out of 100) \\ [1ex] 4 & 71 \\ 2 & 81 \\ 4 & 62 \\ 1 & 86 \\ 3 & 77 \\ 1 & 93 \\ 2 & 84 \\ 3 & 80 \\ 2 & 85 \end{tabular} \end{center}](https://tex.z-dn.net/?f=%5Cbegin%7Bcenter%7D%0A%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0AHours%20Spent%20Watching%20TV%20%26%20Grade%20on%20Test%20%28out%20of%20100%29%20%20%5C%5C%20%5B1ex%5D%0A4%20%26%2071%20%5C%5C%20%0A2%20%26%2081%20%5C%5C%20%0A4%20%26%2062%20%5C%5C%20%0A1%20%26%2086%20%5C%5C%20%0A3%20%26%2077%20%5C%5C%20%0A1%20%26%2093%20%5C%5C%20%0A2%20%26%2084%20%5C%5C%20%0A3%20%26%2080%20%5C%5C%20%0A2%20%26%2085%0A%5Cend%7Btabular%7D%0A%5Cend%7Bcenter%7D)
Let the number the number of hours of television each of the students watched the night before the test be x while the grades they each earned on that test be y.
We use the following table to find the equation of the line of best fit of the regression analysis of the data.
![\begin{center} \begin{tabular} {|c|c|c|c|} x & y & x^2 & xy \\ [1ex] 4 & 71 & 16 & 284 \\ 2 & 81 & 4 & 162 \\ 4 & 62 & 16 & 248 \\ 1 & 86 & 1 & 86 \\ 3 & 77 & 9 & 231 \\ 1 & 93 & 1 & 93 \\ 2 & 84 & 4 & 168 \\ 3 & 80 & 9 & 240 \\ 2 & 85 & 4 & 170 \\ [1ex]\Sigma x=22 & \Sigma y=719 & \Sigma x^2=64 & \Sigma xy=1,682 \end{tabular} \end{center}](https://tex.z-dn.net/?f=%5Cbegin%7Bcenter%7D%20%5Cbegin%7Btabular%7D%20%7B%7Cc%7Cc%7Cc%7Cc%7C%7D%20x%20%26%20y%20%26%20x%5E2%20%26%20xy%20%5C%5C%20%5B1ex%5D%204%20%26%2071%20%26%2016%20%26%20284%20%5C%5C%202%20%26%2081%20%26%204%20%26%20162%20%5C%5C%204%20%26%2062%20%26%2016%20%26%20248%20%5C%5C%201%20%26%2086%20%26%201%20%26%2086%20%5C%5C%203%20%26%2077%20%26%209%20%26%20231%20%5C%5C%201%20%26%2093%20%26%201%20%26%2093%20%5C%5C%202%20%26%2084%20%26%204%20%26%20168%20%5C%5C%203%20%26%2080%20%26%209%20%26%20240%20%5C%5C%202%20%26%2085%20%26%204%20%26%20170%20%5C%5C%20%5B1ex%5D%5CSigma%20x%3D22%20%26%20%5CSigma%20y%3D719%20%26%20%5CSigma%20x%5E2%3D64%20%26%20%5CSigma%20xy%3D1%2C682%20%5Cend%7Btabular%7D%20%5Cend%7Bcenter%7D)
Recall that the equation of the line of best fit of a regression analysis is given by

where:

and


Thus, the equation of the line of best fit is given by y = 97.95 - 7.391x
<span>A student that watched 1.5 hours of TV will have a score given by
y = 97.95 - 7.391(1.5) = 97.95 - 11.0865 = 86.8635
Therefore, </span><span>a student’s score if he/she watched 1.5 hours of TV to the nearest whole number is 87.</span>
Ok so one way is to list the multiplues of 9 close to thtat
first use a caltulator to find out how much more we need
160/9=17.777777
that is 17.7777 nine's
so round up
18
18 is even
odd times even=even
18 must be odd
18+1=19
9 times 19=171
the answer is 171