This is a combination problem.
6 nCr 2

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<u><em>The </em></u><u><em>number of trains</em></u><u><em> that arrived Dubai metro station on time is; 272 trains. </em></u>
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- We are told that 320 trains arrived the Dubai metro station in a week.
- Now, we are told that 5% got there early and 15% got there late.
This means, the percentage that got there on time is;
100% - % of trains that got there late.
- Therefore, percentage of trains that got there on time is;
100% - 15% = 85%
- Since 85% of the trains got there on time, then number of trains that got there on time is;
85% × 320 = 272
- Therefore, we can conclude that 272 trains arrived on time.
Read more at; brainly.in/question/33336249
The solution is the point of intersection between the two equations.
Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.
In the graph the first equation is in blue and the second in red.
The point of intersection = the solution = (-6 , -1)
If you dont have access to a graphing calculator you could draw the graphs by hand;
1) Draw a table of values for each equation; you do this by setting three or four values for x and calculating its image in y (you can use any values of x)
y = 0.5 x + 2 (Im writing 0.5 instead of 1/2 because I find its easier in this format)
x | y
-1 | 1.5 * y = 0.5 (-1) + 2 = 1.5
0 | 2 * y = 0.5 (0) + 2 = 2
1 | 2.5 * y = 0.5 (1) + 2 = 2.5
2 | 3 * y = 0.5 (2) + 2 = 3
y = x + 5
x | y
-1 | 4 * y = (-1) + 5 = 4
0 | 5 * y = (0) + 5 = 5
1 | 6 * y = (1) + 5 = 6
2 | 7 * y = (2) + 5 = 7
2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph
3) Using a ruler draw a line connection all the dots of one graph and do the same for the other
4) The point of intersection is the solution
Answer: 3/8
Step-by-step explanation:
When three coins are flipped, we get 8 total outcomes: (HHH,HHT,HTH,HTT,THH,THT,TTH,TTT)
Two tails and one head is (HTT, TTH, THT)
Probability = number of favorable outcomes/ number of total outcomes
Number of Favorable outcomes = 3
Number of Total outcomes= 8
Therefore, probability of getting 2 tails and one head
= 3/8