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mojhsa [17]
3 years ago
9

Find the volume of the sphere

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0
The volume of a sphere is
(4/3)πr²
Radius is 9
(4/3)π9²
= 339.12 units³
ioda3 years ago
5 0

Volume of a sphere of radius r is

V = (4/3)πr³

r = 9

V = (4/3)π(9³) = 12(9²)π = 972 π

Answer : 972π cubic units

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Katarina [22]

Answer: 82.40

Step-by-step explanation: I took the quiz

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3 years ago
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If 17,000 is 47% what is 100%<br> Please explain!
Alja [10]

Answer:

36,170.21276595745 (I did this on a calculator.)

Step-by-step explanation:

17000/47 = 361.7021276595745

361.7021276595745 x 100 = 36,170.21276595745

Your total answer is 36,170.21276595745.

8 0
3 years ago
What is the slope of a line parallel to the line whose equation is3x−4y=8?
xxTIMURxx [149]

The slope of the parallel line is 3/4

<h3>How to determine the slope?</h3>

The equation is given as:

3x - 4y = 8

Rewrite as:

4y = 3x - 8

Divide through by 4

y = 3x/4 -  2

A linear equation is represented as:

y = mx + b

Where m represents the slope

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m = 3/4

Parallel lines have equal slope

Hence, the slope of the parallel line is 3/4

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brainly.com/question/3493733

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7 0
2 years ago
17. You roll a number cube. How likely is it that you will roll a number less than 7? <br> Explain
Lyrx [107]

Answer:

1 or 100%.

Step-by-step explanation:

The probability of rolling less than 7 is equal to the probability of rolling 1 or 2 or 3 or 4 or 5 or 6. That is 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 6/6. So any number from the dice can come up when you roll it because a perfect dice has 6 sides.

6 0
2 years ago
Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,
sweet [91]

Answer:

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

f'' = x - \frac{3}{2}

f' = \int {\left(x-\frac{3}{2}\right) } \, dx

f' = \int {x} \, dx -\frac{3}{2}\int \, dx

f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C, where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative (f'(4) = 1):

1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C

C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)

C = -1

The first derivative is y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1, and the particular solution is found by integrating one more time and using the initial condition (f(0) = 0):

y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1  \right)} \, dx

y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx

y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C

C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0

C = 0

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

5 0
3 years ago
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