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sp2606 [1]
3 years ago
6

NEED ANSWERED ASAP 1.find the volume of a cone with height of 12 inches and a base diameter of 6 in. use 3.14 for pie and do not

round
2. A company makes cones out of solid foam each cone has a height of 15 in and a base has a diameter of 3 in how much foam is needed to make 160 cones . use 3.14 for pie and do not round​

Mathematics
1 answer:
34kurt3 years ago
5 0

Answer:

Check photo below.

Step-by-step explanation:

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The volleyball team sold 16 items on the first day of a bake sale, 28 items on the second day, and 12 items on the last day. The
valina [46]
60 items were for sale because you need to add together the amounts that were sold plus what was left over, giving you everything that they had for sale.
6 0
3 years ago
Please answer with explanation of how you got the answer !!
Irina18 [472]

Answer:

−24

Step-by-step explanation:

Since there is only one negative, this means when all the values are multiplied together the product will be negative. Just multiply all three together to get −24.

(3)(−4)(2)

(−12)(2)

−24

It doesn't matter which order you multiply in in this case.

7 0
3 years ago
Solve x2 – 4x – 9 = 29 for x.
Irina-Kira [14]
x^2 - 4x - 9 = 29 \\ x^2 - 4x - 9 - 29 = 0 \\ x^2 - 4x - 38 = 0 \\ x= \frac{-b \pm  \sqrt{ b^{2} -4ac} }{2a} 
; where a = 1, b = -4 and c = -38
x= \frac{-(-4) \pm 
\sqrt{ 
(-4)^{2} -4 \times 1 \times -38} }{2 \times 1} \\ = \frac{4 \pm \sqrt{ 16 +152} }{2} \\ =\frac{4 \pm \sqrt{ 168} }{2} \\ =\frac{4 \pm 
2\sqrt{42} }{2} \\ 
=2+\sqrt{42} \ or \ 2-\sqrt{42}\\=8.48 \ or \ -4.48







8 0
3 years ago
Read 2 more answers
90 POINTS| PLEASE ANSWER ASAP|
shtirl [24]

For A:

You add the probabilities to get the answer to A: = .75, or 3/4

Note that the probability of ALL THREE of them hitting would be 1/3 x 1/4 x 1/5.

For B:

2/3 and 3/4 is the probability of the other two people MISSING (the remainder of 1/3, 1/4)

1.0 = 100% chance to hit the target, so 1.0 x 2/3 x 3/4 = 1/2

Mark's chance of hitting is 1/5, so do 1/2 x 1/5, = 1/10

5 0
3 years ago
Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

8 0
1 year ago
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