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photoshop1234 [79]
3 years ago
14

URGENT again having difficulty, please answer as soon as possible would be appreciate it :)

Mathematics
1 answer:
aliina [53]3 years ago
6 0
1. X=-2 x=1 x=5/2
2. X=0 x=-1/5 x=4/3 x=1
3.x>-2
4.X>_8
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6. Andy scored 90 on the last history exam. He scored 81 this time. By what percent did his score decrease?​
allsm [11]

Answer:

His score decreased by 9 percent this time.

Step-by-step explanation:

From his first history exam he had a score of 90 percent. The difference between his first score and present score is given by

90 - 81 = 9

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2 years ago
Can a vector have a component greater than the vector's magnitude ?<br>​
Mars2501 [29]
Answer: No, it can never be greater. At most it can be equal though.

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2 years ago
What is the distance between (5,10) and (5,2)?
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3 years ago
The mean finish time for a yearly amateur auto race was 186.32 minutes with a standard deviation of 0.305 minute. The winning​ c
uranmaximum [27]

Complete Question

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.305 minute. The winning car, driven by Roger, finished in 185.85 minutes. The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

Find their respective z-scores.

 Who had the more convincing victory?

A. Roger​ had a more convincing victory because of a higher z-score.

B. Karen a more convincing victory because of a higher z-score.

C. Roger had a more convincing victory, because of a lower z-score.

D. Karen a more convincing victory because of a lower z-score.

Answer:

The correct option is  D

Step-by-step explanation:

From the question we are told that

  The mean of the current year  is  \mu_c =  186.32 \  minutes

   The standard deviation is  \sigma_c  =  0.305 \  minutes

   The time taken by  the winning car for the current year  is  x =  185.85 \ minutes

  The mean of the previous  year  is  \mu_p =  110.7 \  minutes

   The standard deviation the previous  year  is  \sigma_p  = 0.115  \  minutes

 The time taken by  the winning car for the previous year  is  y =   110.48 \ minutes    

Generally the z-score for current year is mathematically evaluated as

     z_c  =  \frac{x- \mu_c}{\sigma_c }

=>     z_c  =  \frac{ 185.85- 186.32}{0.305 }

=> z_c  = -1.536

Generally the z-score for previous year is mathematically evaluated as

     z_p  =  \frac{y- \mu_p}{\sigma_p }

=>     z_p  =  \frac{ 110.48-110.7}{0.115  }

=> z_p  = -1.913

From the value obtained we see that  z_p  <  z_c , Hence  Karen had a more convincing victory because of the lower z -score.

5 0
2 years ago
How do the last four lines of the poem contribute to the poems overall structure. help me pls!
Artist 52 [7]

The last four linesof the poem reveals the solution in the poem as the first reveals the problem

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2 years ago
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