Answer:
(-5,-14)
Step-by-step explanation:
To find the solution of the system of two equations
equate right sides of these two equations:
Rewrite terms with x into the left side and without x into the right side:
![4x-2x=-4-6\\ \\2x=-10\ [\text{divide by 2}]\\ \\x=-5](https://tex.z-dn.net/?f=4x-2x%3D-4-6%5C%5C%20%5C%5C2x%3D-10%5C%20%5B%5Ctext%7Bdivide%20by%202%7D%5D%5C%5C%20%5C%5Cx%3D-5)
Substitute x=-5 into the first equation:
The solution is (-5,-14)
9514 1404 393
Answer:
Step-by-step explanation:
The outside factor multiplies each term in parentheses.
a) 2(b+c) = 2b +2c
b) 5(7h +3m) = 5×7h +5×3m = 35h +15m
c) e(f +g) = ef +eg
Answer:
y = x - 2
Step-by-step explanation:
y = mx + b
5 = 1 (7) + b
5 = 7 + b
b = -2
So...
y = x - 2
The best answer is 1.435 ·103 because while they both are really small for a rail road track that one is bigger. the final answer for that is 147.805mm.
Answer:
80/81
Step-by-step explanation:
If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.
The probability of getting at least 1 head involves 4 scenarios:
1) 1 Head and 3 Tails
2) 2 Heads and 2 Tails
3) 3 Heads and 1 Tail
4) 4 Heads
Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:
P(at least one head) + P(no heads) = 1
Then, P(at least one head) = 1 - P(no heads)
The probability of 4 tails is:
P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81
Then, P(at least one head) = 1 - 1/81=80/81
