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stealth61 [152]
3 years ago
7

Help me find area and perimeter of this problem

Mathematics
1 answer:
mylen [45]3 years ago
7 0

Answer: 16.28

Step-by-step explanation: You need to find the area of the half circle so 4*3.14 dvided by 2 that is 6.28 then for the tryangle you do base times hight devided by 2 and you get 10 so add then and it should be 16.28

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The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth
Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

(c) The probability that at least three of the selected computers are desktops is 0.401.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = P(Laptop) = p_{X} = \frac{4}{9}

The probability of selecting a desktop is = P(Desktop) = p_{Y} = \frac{5}{9}

Then both X and Y follows Binomial distribution.

X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})

The probability function of a binomial distribution is:

P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: {n\choose k}=\frac{n!}{k!(n-k)!}

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

{8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\  =0.304832\\\approx0.305

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

P(Y\geq 3)=1-P(Y

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0
3 years ago
Standard form four hundred and five hundredths
galben [10]
400.05 is the answer.
8 0
3 years ago
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646 is 85% of what number?
Lilit [14]

Let the number be y

The statement can be interpreted as

85% of y = 646

\begin{gathered} \text{ }\frac{85}{100}\text{ x  y = 646} \\ 85y\text{ = 64600} \\ y=\frac{64600}{85} \\ y=760 \\ \text{  The number is 760} \end{gathered}

8 0
1 year ago
If someone worked 10 :00 to 1:00 how many hours would they have worked
nirvana33 [79]
10 to 11 = 1 hr
11 to 12 = 1 hr
12 to 1 = 1 hr

total  = 3 hours
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The 8th term is 33 and I don't think any of the options are there
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