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krok68 [10]
3 years ago
14

3/4 times 2/4 thank you

Mathematics
1 answer:
irinina [24]3 years ago
8 0

Answer:

3/8 (0.375)

Step-by Step:

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40-50-60<br>Work out<br>2 × 1/7 -1 2/5<br>Give your answer in its simplest form.​
MAVERICK [17]

Answer:

the simplest form of the given expression is -1\frac{4}{35}

Step-by-step explanation:

Given;

2 \times  \frac{1}{7}  -  1\frac{2}{5}

The above expression can be simplified as follows;

2 \times  \frac{1}{7}  -  1\frac{2}{5} \\\\=\frac{2}{7} - \frac{7}{5} \\\\= l.c.m \ of \ 7 \ and \ 5 \ is \ 35\\\\= \frac{5(2) - 7(7)}{35} \\\\= \frac{10 - 49}{35} \\\\= -\frac{39}{35} \\\\= - 1\frac{4}{35}

Therefore, the simplest form of the given expression is -1\frac{4}{35}

5 0
3 years ago
The booster club needs to raise at least $7000 for new football uniforms
HACTEHA [7]
There is not alot information to answer the question.
6 0
4 years ago
If eg=25 and point f is 2/5 of the way between e and g find the value fg
Aliun [14]
Fg = 15

2/5(25) = 10
25-10 = 15
8 0
3 years ago
Read 2 more answers
*PLEASE ANSWER* The radius of a salad bowl is 7.2 inches. What is the surface area of the bowl? (Assume the bowl is half a spher
Kruka [31]

Answer:

a) 325.72

Step-by-step explanation:

A=4pir^2

A=4x3,14x7.2x7.2

a=651.44

1/2a=1/2x651.44

=325.72

3 0
4 years ago
In order to conduct an experiment, 4 subjects are randomly selected from a group of 20 subjects. How many different groups of fo
irga5000 [103]

Answer:

The number of ways to form different groups of four subjects is 4845.

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

In this case, 4 subjects are randomly selected from a group of 20 subjects.

Compute the number of ways to form different groups of four subjects as follows:

{n\choose k}=\frac{n!}{k!\times (n-k)!}

{20\choose 4}=\frac{20!}{4!\times (20-4)!}

      =\frac{20\times 19\times 18\times 17\times 16!}{4!\times 16!}\\\\=\frac{20\times 19\times 18\times 17}{4\times3\times 2\times 1}\\\\=4845

Thus, the number of ways to form different groups of four subjects is 4845.

5 0
3 years ago
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