Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
y=2x+4
Step-by-step explanation:
8=2(6)+b
8=12+b
4=b
(2/3)(1/4)=
2/12=
1/6
multiply the numerators by the numerators, (top numbers)
and the denominators by the denominators, (bottom numbers)
We know that
the coordinates of point B ( -5,0)
the translation has the following rule
(x,y)--------> (x+5, y-2)
so
(-5,0)-----> (-5+5,0-2)-----> (0,-2)
the answer is
<span>(0, –2) </span>
