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juin [17]
3 years ago
9

Dunno what i'm exactly supposed to be doing here?

Mathematics
2 answers:
OverLord2011 [107]3 years ago
7 0
You have to add the first year then for the 2nd year you have to add the estimated difference
Tcecarenko [31]3 years ago
4 0
The total change means add the changes from each year
-1 3/5 + (- 2 1/15) = 
-8/5 - 31/15 =
-24/15 - 31/15 =
-55/15 = - 3 2/3<== the total change

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What is the value of f(x)=-3.25x 22.41 at x=-4.2
Gennadij [26K]
F(x)=-3.25x +22.41
f(-4.2)= 3.25(-4.2)+22.41 = 8.76
4 0
4 years ago
3.6+7.2k &lt;25.2 what the answer
ArbitrLikvidat [17]
Here are the steps to solving:
1) Write out problem      3.6+7.2k <25.2
2) Subtract 3.6                      7.2k <21.6
3) Divide by 7.2                          k <3

So k<3 would be your answer
8 0
3 years ago
If a 32 ft rope is cut into two sections with one section 7 times as log as the other section, how long is teh shorter piece?
steposvetlana [31]
The total length of the rope = 32 ft
It is cut into two sections, say x and y
But one section is seven times the other, say y=7x (shorter section being x)
Solving for x

x+y =32
x+7x = 32
8x=32
x=32/8 = 4 ft.
Therefore, the shorter piece is 4 ft long.
5 0
3 years ago
2(12x + 16y) + 5(3y +4z) + 7(6x – 3y - 2z)
Phantasy [73]

Answer:

52x + 26y + 20z

Step-by-step explanation:

Assuming you needed the answer to be simplified!

7 0
3 years ago
Solve the equation<br> 7x25=30
oksian1 [2.3K]

Answer:

x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

Step-by-step explanation:

Solve for x:

7 x^25 = 30

Hint: | Divide by an appropriate factor to make the coefficient of x^25 equal to 1.

Divide both sides by 7:

x^25 = 30/7

Hint: | Take 25^th roots of both sides.

Taking 25^th roots gives (30/7)^(1/25) times the 25^th roots of unity:

Answer: x = -(-30/7)^(1/25) or x = (30/7)^(1/25) or x = (-1)^(2/25) (30/7)^(1/25) or x = -(-1)^(3/25) (30/7)^(1/25) or x = (-1)^(4/25) (30/7)^(1/25) or x = -(-1)^(1/5) (30/7)^(1/25) or x = (-1)^(6/25) (30/7)^(1/25) or x = -(-1)^(7/25) (30/7)^(1/25) or x = (-1)^(8/25) (30/7)^(1/25) or x = -(-1)^(9/25) (30/7)^(1/25) or x = (-1)^(2/5) (30/7)^(1/25) or x = -(-1)^(11/25) (30/7)^(1/25) or x = (-1)^(12/25) (30/7)^(1/25) or x = -(-1)^(13/25) (30/7)^(1/25) or x = (-1)^(14/25) (30/7)^(1/25) or x = -(-1)^(3/5) (30/7)^(1/25) or x = (-1)^(16/25) (30/7)^(1/25) or x = -(-1)^(17/25) (30/7)^(1/25) or x = (-1)^(18/25) (30/7)^(1/25) or x = -(-1)^(19/25) (30/7)^(1/25) or x = (-1)^(4/5) (30/7)^(1/25) or x = -(-1)^(21/25) (30/7)^(1/25) or x = (-1)^(22/25) (30/7)^(1/25) or x = -(-1)^(23/25) (30/7)^(1/25) or x = (-1)^(24/25) (30/7)^(1/25)

4 0
4 years ago
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