The length of a swimming pool would be about

Solve the system using the addition method. State your solution as an ordered pair.

vladimir1956 [14]

Solution as ordered pair is:

(5, $\frac{41}{2}$ )

Step-by-step explanation:

Solving the system of equations:

$3x+2y=56\,\,\,(1)\\9x-2y=4\,\,\,(2)$

Adding equation(1) and equation(2)

$3x+2y=56\\9x-2y=4\\--------\\12x=60\\x=\frac{60}{12}\\x=5$

Putting value of x i.e x=5 in equation(1)

$3x+2y=56\\3(5)+2y=56\\ 15+2y=56\\2y=56-15\\2y=41\\y=\frac{41}{2}\\y=\frac{41}{2}$

So, value of x=5 and y= $\frac{41}{2}$

Solution as ordered pair is:

(5, $\frac{41}{2}$ )

Keywords:System of Equations

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6 0

3 years ago

The area of a trapezoid is 144 square inches. if the height is 12 inches, find the length of the median.

deff fn [24]

Answer: 12 inches

Step-by-step explanation: In this problem, since we're asked to find the length of the median, let's use our formula for the area of a trapezoid that involves the median which is shown below.

Area = median · height

We know that the area is 144 and the height is 9 so we can set up the equation 144 = M · 12. Now to solve for <em>m</em>, we divide both sides of the equation by 12 and we find that 12 = M.

So the length of the median of the trapezoid is 12 inches.

6 0

3 years ago

Solve the following equations for y.<br> 9. 2y + 3= 2x

Dahasolnce [82]

Answer:

y = x − 3 /2

Step-by-step explanation:

4 0

3 years ago

HELP ASAP!! Identify the matrix transformation of ΔPQR, which has coordinates P(−5, −2),Q(−6, −3), and R(−2, −3), for reflection

podryga [215]

Answer:

Matrix transformation = $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ .

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-5\\-2\end{array}\right]$ = (5,-2)