Find the sum of these polynomials. (x^2

Kayla sold half of her comic books and then bought seven more. she now has 28. with how many did she begin

bezimeni [28]

28 - 7 = 21
21 x 2 = 42

7 0

3 years ago

Please help asap!!! i dont understand it

pshichka [43]

Answer:

a

Step-by-step explanation:

A perpendicular bisector, intersects a line at its mid point and is perpendicular to it.

Calculate slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13)

m = $\frac{13-1}{9-(-7)}$ = $\frac{12}{9+7}$ = $\frac{12}{16}$ = $\frac{3}{4}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{3}{4} }$ = - $\frac{4}{3}$ ← slope of perpendicular bisector

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

using (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13) , then

midpoint = ( $\frac{-7+9}{2}$ , $\frac{1+13}{2}$ ) = ( $\frac{2}{2}$ , $\frac{14}{2}$ ) = (1, 7 )

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - $\frac{4}{3}$ , then

y = - $\frac{4}{3}$ x + c ← is the partial equation

To find c substitute the midpoint (1, 7) into the partial equation

7 = - $\frac{4}{3}$ + c ⇒ c = $\frac{21}{3}$ + $\frac{4}{3}$ = $\frac{25}{3}$

y = - $\frac{4}{3}$ x + $\frac{25}{3}$ ← equation of perpendicular bisector

7 0

3 years ago

Identify the denominator in the following radical .

Anna71 [15]

There is no exercise. I cannot answer it without an exercise.

7 0

3 years ago

Find the indefinite integrals, if possible, using the formulas and techniques you have studied so far in the text.(a) 11 x4 dxTh

hoa [83]

Answer:

a) This integral can be evaluated using the basic integration rules. $\int 11x^{4}dx = \frac{11}{5} x^{5}+C$

b) This integral can be evaluated using the basic integration rules. $\int 8x^{1}x^{4}dx=\frac{4}{3}x^{6}+C$

c) This integral can be evaluated using the basic integration rules. $\int 3x^{31}x^{4}dx=\frac{x^{36}}{12}+C$

Step-by-step explanation:

a) $\int 11x^{4}dx$

In order to solve this problem, we can directly make use of the power rule of integration, which looks like this:

$\int kx^{n}=k\frac{x^{n+1}}{n+1}+C$

so in this case we would get:

$\int 11x^{4}dx=11 \frac{x^{4+1}}{4+1}+C$

$\int 11x^{4}dx=11 \frac{x^{5}}{5}+C$

b) $\int 8x^{1}x^{4}dx$

In order to solve this problem we just need to use some algebra to simplify it. By using power rules, we get that:

$\int 8x^{1}x^{4}dx=\int 8x^{1+4}dx=\int 8x^{5}dx$

So we can now use the power rule of integration:

$\int 8x^{5}dx=\frac{8}{5+1}x^{5+1}+C$

$\int 8x^{5}dx=\frac{8}{6}x^{6}+C$

$\int 8x^{5}dx=\frac{4}{3}x^{6}+C$

c) The same applies to this problem:

$\int 3x^{31}x^{4}dx=\int 3x^{31+4}dx=\int 3x^{35}dx$

and now we can use the power rule of integration:

$\int 3x^{35}dx=\frac{3x^{35+1}}{35+1}+C$

$\int 3x^{35}dx=\frac{3x^{36}}{36}+C$

$\int 3x^{35}dx=\frac{x^{36}}{12}+C$

6 0

3 years ago

6th grade math! Help me please :)

GREYUIT [131]

Hey there!

The answer is D. 8,512

The value of 5 in Andrew’s number is in the tens place along with answer choices A, B, and C. The only number that has a 5 digit in the HUNDREDS value is D. 8,512

Hope this helped!

7 0

3 years ago

Find the sum of these polynomials. (x^2 - x + 7) + (9x^2 + 6)