Which of the following is an arithmetic sequence?

Based on the two different purchases, you can write equations for the price of a hotdog (h) and that of a drink (d). These equations can be solved by your favorite method to find the individual prices.

... 6h +4d = 17.00 . . . . . . Carl's purchase

... 3h +4d = 12.50 . . . . . . Susan's purchase

We can see that the difference in purchase cost (of $4.50) is due entirely to the difference in the number of hotdogs (3). Thus, the price of a hotdog must be

... $4.50/3 = $1.50

The 4 drinks are then ($12.50 -4.50) = $8, so must be $2 each. You don't need to figure the cost of a drink to determine that the appropriate answer choice is ...

... D. $1.50 for a hot dog; $2.00 for a drink.

5 0

2 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago

Fwam surveyed 540 of the students in his school about their favorite color. students could choose between red and blue. 55% said

Digiron [165]

Answer:

243 students' favorite color is red

Step-by-step explanation:

if 55% of the students said their favorite color was blue, then 45% chose that red was their favorite color

we can get 45% of 540 using a cross-multiplication equation

45% is 45/100

45/100 is to ?/540

the (?) represents the value of students who chose red as their favorite color (we do not know this but we can figure it out using cross-multiplication)

45 times 540 is 24300

24300/100 = 243.

Give brainliest, please!

hope this helps :)

4 0

1 year ago