If log x - log(2x-1)=1 find x
2 answers:
Answer:
x = 10/19
Step-by-step explanation:

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f (x) = log ( 1+x / 1-x ) ---- 1
f ( 2x / 1+x2 ) = ???
to find this ----- in equation 1 replace "x" by ( 2x / 1+x2 )
then
f ( 2x / 1+x2 ) = log ( 1 + x2 + 2x / 1 + x2 - 2x )
f ( 2x / 1+x2 ) = log ( 1+x / 1-x ) 2
f ( 2x / 1+x2 ) = 2 log ( 1+x / 1-x )
f ( 2x / 1+x2 ) = 2 f(x)
Cheers....
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Answer: 3y⁴(y² + 5)(y - 1)(y + 1)
<u>Step-by-step explanation:</u>
3y⁸ + 12y⁶ - 15y⁴
= 3y⁴(y⁴ + 4y² - 5)
= 3y⁴(y² + 5)(y² - 1)
= 3y⁴(y² + 5)(y - 1)(y + 1)
Multiply the numerators together. Multiply the denominators together. Then reduce if necessary.


