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Paul [167]
3 years ago
5

The area of a rectangle is 72 square feet. Its length is 12 feet. Which equivalent formula could you use to find the width?

Mathematics
1 answer:
klasskru [66]3 years ago
4 0

Answer:

w=6ft

Step-by-step explanation:

72 divided by 12 is 6

Using the formula

A=wl

Solving for w

w=A

l=72

12=6ft

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Find the distance traveled in 35 seconds by an object traveling at a velocity of v(t) = 20 + 5cos(t) feet per second
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s(t)= \int\limits^{35}_0 {v(t)} \, dt \\ =\int\limits^{35}_0 {(20+5cos(t))} \, dt \\ =[20t+5sin(t)]^{35}_0 \\ =(20(35)+5sin(35))-(20(0)+5sin(0)) \\ =700+2.868=702.868 \, feet
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Are rectangles ABCD and WXYZ congruent? Why or why not? Yes, all right angles were preserved. Yes, both rectangles have an area
Setler79 [48]

Answer:

D. No, there is not a rigid transformation or a combination of rigid transformations that will map ABCD to WXYZ.

Step-by-step explanation:

Two figures are congruent if their vertices can be mapped into one another by appropriate rigid transformation or combination of rigid transformations. Examples of the transformation are; reflection, dilation, rotation and translation.

Comparing the two figures, it would be observed that they are not congruent. Since there is not a rigid transformation or a combination of rigid transformations that will map ABCD to WXYZ.

3 0
3 years ago
Read 2 more answers
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Alexandra [31]

Answer:

Step-by-step explanation:

2 cos x + √ 2 = 0

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so to solve we have to use  "co-terminal " angles .. do you know what I'm saying?  do you understand the words coming out of my mouth :DDDDD OKay back to math and not movie lines .. :P

x = arcCos(  √ 2  / 2 )

x = 45 °

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notice how it's  1,2,3,4    .. so it's super easy to remember.. the trig books don't show you this "trick"   :P

copy and paste this to your computer some where handy

Sin(0) = 0/2      =0  

Sin(30)= \sqrt{1}/2   = 1/2  

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Sin(60)=\sqrt{3}/2   = \sqrt{3}/2  

Sin(90)=\sqrt{4}/2   = 1  

Cos is exactly the same but counts backwards from 90°

Cos(90) = 0/2       = 0

Cos(60) = \sqrt{1} /2   = 1/2

Cos(45) = \sqrt{2}/2    =\sqrt{2}/2

Cos(30) = \sqrt{3}/2   =\sqrt{3}/2

Cos(0) = \sqrt{4}/2    = 1

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