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Y_Kistochka [10]
3 years ago
15

How to slove that mathematical question in the picture

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0
Get closer!
cant see!
You should come closer!

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(100) points!!!! Help please
inysia [295]

Answer:

\displaystyle a_8=142,11\ mg

Step-by-step explanation:

Geometric sequence

Each term in a geometric sequence can be computed as the previous term by a constant number called the common ratio. The formula to get the term n is

\displaystyle a_n=a_1r^{n-1}

where a_1 is the first term of the sequence

The problem describes Georgie took 275 mg of the medicine for her cold in the first hour and that in each subsequent hour, the amount of medicine in her body is 91% (0.91) of the amount from the previous hour. It can be written as

amount in hour n = amount in hour n-1 * 0.91

a)

This information provides the necessary data to write the general term as

\displaystyle a_n=275\ .\ 0.91^{n-1}

b)

In the 8th hour (n=8), the remaining medicine present is Georgie's body is

\displaystyle a_n=275\ .\ 0.91^{8-1}

\displaystyle a_n=275\ .\ 0.91^{7}

\boxed{\displaystyle a_8=142,11\ mg}

6 0
3 years ago
Write an equation in point-slope form of the line that passes through (-1, – 4) with slope -2.
Rom4ik [11]
Y+4=-2(x+1)

This is the point slope form (y-y1) =m(x-x1)

I hope it will helped!
4 0
3 years ago
PLEASE HELP ME 50 PTS and i'll give brainliest please help me this is the video they game me to do this hw but I still don't und
grigory [225]

1.) 70x/100x^2 = 7/10x

2.) 16x^3/24x = 2x^2/3

3.) 7x(2x+1)/21(2x+1) = x/3

4.) 35x - 35/x^2 - 1 =  35/x + 1

5.) x + 7/x^2 + 4x - 21 = 1/x - 3

6.) x^2 - 6x + 5 = x - 5/5

7.) x^2 - 36/x^2 - 3x - 18 = x + 6/x + 3

8.) x^2 - 3x - 10/x^2 + x - 2 = x - 5/x - 1

3 0
3 years ago
Urgent answers with answers
Ivahew [28]

Step-by-step explanation:

the highest age range are 15,25 and 35.

They have the highest frequency

8 0
4 years ago
Evaluate r=5
Salsk061 [2.6K]

Answer:

\sum (r+1)^2 = 90

Step-by-step explanation:

Given

\sum (r+1)^2; r = 1,2....5

Required

Evaluate

\sum (r+1)^2; r = 1,2....5 is equivalent to :

(1 + 1)^2 +(2 + 1)^2 +(3 + 1)^2 +(4 + 1)^2 +(5 + 1)^2

(2)^2 +(3)^2 +(4)^2 +(5)^2 +(6)^2

4 + 9 + 16 + 25 + 36

90

Hence:

\sum (r+1)^2 = 90

4 0
3 years ago
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