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Tom [10]
3 years ago
7

PLEASE HELP ME 50 PTS and i'll give brainliest please help me this is the video they game me to do this hw but I still don't und

erstand it https://youtu.be/7Uos1ED3KHI

Mathematics
1 answer:
grigory [225]3 years ago
3 0

1.) 70x/100x^2 = 7/10x

2.) 16x^3/24x = 2x^2/3

3.) 7x(2x+1)/21(2x+1) = x/3

4.) 35x - 35/x^2 - 1 =  35/x + 1

5.) x + 7/x^2 + 4x - 21 = 1/x - 3

6.) x^2 - 6x + 5 = x - 5/5

7.) x^2 - 36/x^2 - 3x - 18 = x + 6/x + 3

8.) x^2 - 3x - 10/x^2 + x - 2 = x - 5/x - 1

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The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.
Ulleksa [173]

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0.52763 is the probability that the time between the next two calls will be 54 seconds or​ less.

0.19285 is the probability that the time between the next two calls will be greater than 118.5 ​seconds.

Step-by-step explanation:

We are given the following information in the question:

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.

The distribution function can be written as:

f(x) = \lambda e^{-\lambda x}\\\text{where lambda is the parameter}\\\\\text{Mean} = \mu = \displaystyle\frac{1}{\lambda}\\\\\Rightarrow 1.2 = \frac{1}{\lambda}\\\\\lambda = 0.84 \\f(x) = 0.84 e^{0.84 x}

The probability for exponential distribution is given as:

P( x \leq a) = 1 - e^{\frac{-a}{\mu}}\\\\P(a \leq x \leq b) = e^{\frac{-a}{\mu} -\frac{-b}{\mu}}

a) P( time between the next two calls will be 54 seconds or​ less)

P( x \leq 0.9)\\= 1 - e^{\frac{\frac{-54}{60}}{1.2}} = 0.52763

0.52763 is the probability that the time between the next two calls will be 54 seconds or​ less.

b) P(time between the next two calls will be greater than 118.5 ​seconds)

p( x > \frac{118.5}{60}) = P(x > 1.975)\\\\ = 1 - P(x \leq 1.975) \\\\= 1 -1+ e^{\frac{-1.975}{1.2}}\\\\= 0.19285

0.19285 is the probability that the time between the next two calls will be greater than 118.5 ​seconds.

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