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Damm [24]
3 years ago
7

In ΔVWX, the measure of ∠X=90°, the measure of ∠W=25°, and WX = 61 feet. Find the length of XV to the nearest foot.

Mathematics
1 answer:
dlinn [17]3 years ago
4 0
Check the picture below.

make sure your calculator is in Degree mode.

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There are 32 marbles in the box. There are 12 red marbles, 14 blue marbles, and 6 yellow marbles. What percent of the marbles ar
Umnica [9.8K]

Answer:

Around 82-81% aren't yellow.

Step-by-step explanation:

Add together the number of marbles that aren't yellow and divide the total of <u>NON YELLOW</u> with the total (32) to get around 82-81%.

6 0
2 years ago
Please help with this! :)
olchik [2.2K]

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4 and 3 <------- That's the set I believe!

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3 years ago
Harry worked 7 hours last week. This is 1__3as many hours as Aidan worked. How many hours did Aidan work?
vitfil [10]

Answer:

21

Step-by-step explanation:

1/3= 0.33

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7 0
2 years ago
Carl is boarding a plane. He has 2 checked bags of equal weight and a backpack that weighs 4 kg. The total weight of Carl's bagg
aniked [119]
<span>Carl has 3 bags in total. One backpack weighs 4 kg and the rest two checking bags have the equal weight. The total weight of 3 bags is given to be 35 kg.

Let the weight of each checking bag is w kg. So we can write:

2 x (Weight of a checking bag) + Weight of Backpack = 35

Using the values, we get:

2w+ 4 = 35

Using this equation we can find the weight of each checking bag, as shown below.

2w = 31

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5 0
3 years ago
Read 2 more answers
7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.
blondinia [14]

\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill

\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}

7 0
1 year ago
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