Answer:
2/25. Hope this helps :) :) :) :)
Answer:
y = Ax^2
Step-by-step explanation:
below is the detailed solution
To determine the orthogonal trajectories of the family of curves
X^2 + 2y^2 = 17k^2
we have to differentiateX^2 + 2y^2 = 17k^2 with respect to x
= 2x + 4y dy/dx = 0
Hence : dy/dx = - x/2y
we have to determine the negative reciprocal
dy/dx = 2y/x ----------- 1
integrate equation 1
∫dy/2y = ∫dx/x
= 1/2 log y = log x + log c
log y = 2logx + 2logc
log y = logx^2 + logC^2
therefore : y = Ax^2 ; where C^2 = A
Answer:
y = -2x + 3
Step-by-step explanation:
y = -2x + b
3 = -2(0) + b
3 = 0 + b
3 = b
Y/2=1-x
y=2-2x
y(-2)=2-2(-2)=2+4=6, (-2,6)
So (-2, 6) is an ordered pair from x+y/2=1