Question

For each sequence, find the first 4 terms of a sequence: a) n²+3 b) 2n²

Answer 1

Answer:

a) 4, 7, 12, 19

b) 2, 8, 18, 32

Step-by-step explanation:

Sequence is just number line sir, so to begin with you get n=1, then n=2, then n=3, then n=4, these are the first 4 terms

Answer 2

Answer:

a) 4, 7, 12, 19

b) 2, 8, 18, 32

Step-by-step explanation:

In order to find the first 4 terms, you have to substitute 1 to 4 into n for both expressions :

$a) {n}^{2} + 3$

$1st \: term \\ {1}^{2} + 3 = 4$

$2nd \: term \\ {2}^{2} + 3 = 7$

$3rd \: term \\ {3}^{2} + 3 = 12$

$4th \: term \\ {4}^{2} + 3 = 19$

$b)2 {n}^{2}$

$1st \: term \\ 2( {1}^{2} ) = 2$

$2nd \: term \\ 2( {2}^{2} ) = 2(4) = 8$

$3rd \: term \\ 2( {3}^{2} ) = 2(9) = 18$

$4th \: term \\ 2( {4}^{2} ) = 2(16) = 32$