The given plane,
, has normal vector
. Any plane parallel to this one has the same normal vector.
Let
be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

and this is perpendicular to
.
So the equation of the plane is

or equivalently,

Answer:
I think no A. x = -1/2 ,x = -4
The equation is y=2x-2
To find the x-value you take any two pairs of value such as (-2,-3) and (0,-2) and you just use y1-y2/x1-x2. And for y-value you just see when x is zero