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monitta
3 years ago
12

What is the slope of the line passing through the points (2,-5) and (4, 1)? enla

Mathematics
1 answer:
Nookie1986 [14]3 years ago
8 0

Answer:

3

Step-by-step explanation:

dentify the coordinates (x₁,y₁)and(x₂,y₂). We will use the formula to calculate the slope of the line passing through the points (3,8) and (-2, 10).

Input the values into the formula. This gives us (10 - 8)/(-2 - 3).

Subtract the values in parentheses to get 2/(-5).

Simplify the fraction to get the slope of -2/5.

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shusha [124]

The correct answer is c.

a.6/9

b.1/2

<em><u>c.1/3</u></em>

d.3/12



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The solids are similar. Find the volume of the smaller solid.
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the smaller solid is 121.5

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3 years ago
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3 years ago
The number of accidents on a particular highway average 4.4 per year.
MA_775_DIABLO [31]

It is given that number of accidents on a particular highway is average 4.4 per year.

a. Let X be the number of accidents on a particular highway.

X follows Poisson distribution with mean μ =4.4

The probability function of X , Poisson distribution is given by;

P(X=k) = \frac{e^{-4.4} (4.4)^{k}}{k!}

b. Probability that there are exactly four accidents next year, X=4

P(X=4) = \frac{e^{-4.4} (4.4)^{4}}{4!}

P(X=4) = 0.1917

Probability that there are exactly four accidents next year is 0.1917

c. Probability that there are more that three accidents next year is

P(X > 3) = 1 - P(X ≤ 3)

= 1 - [ P(X=3) + P(X=2) + P(X=1) + P(X=0)]

P(X=3) = \frac{e^{-4.4} (4.4)^{3}}{3!}

P(X=3) = 0.1743

P(X=2) = \frac{e^{-4.4} (4.4)^{2}}{2!}

P(X=2) = 0.1188

P(X=1) = \frac{e^{-4.4} (4.4)^{1}}{1!}

P(X=1) = 0.054

P(X=0) = \frac{e^{-4.4} (4.4)^{0}}{0!}

= 0.0122

Using these probabilities into above equation

P(X > 3) = 1 - P(X ≤ 3) = 1 - [ P(X=3) + P(X=2) + P(X=1) + P(X=0)]

= 1 - (0.1743 + 0.1188 + 0.054 + 0.0122)

P(X > 3) = 1 - 0.3593

P(X > 3) = 0.6407

Probability that there are more than three accidents next year is 0.6407

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