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makkiz [27]
3 years ago
12

In 1969 the antique automobile of America had 23,00 members. It grew an average of 5% per year through 1985. Assuming this conti

nued what would the membership be in 2004?
Mathematics
1 answer:
Verizon [17]3 years ago
6 0
A=p (1+r)^t

A membership be in 2004
P membership be in 1969. 2300
R rate 5/100= 0.05
T time 2004-1969

A=2,300×(1+0.05)^(2,004−1,969)
A=12,686.8 round your answer
A=12687 in 2004

Hope it helps:-)
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Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that \mu = 35000, \sigma = 7000

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 35000}{7000}

X - 35000 = -1.88*7000

X = 21840

The designed life should be of 21,840 vehicle miles.

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