By SAS property, ABC ≅ DCB.
<h3>How to prove the deductions</h3>
In this question we have to proof ABCD has congruent diagonal. By SAS property and reflexive property it can be proved as follows:
Given:
ABCD is a rectangle.
Prove:
Diagonal AC ≅ Diagonal BD
From the question,
As we can see that, ABCD is a rectangle, it is also a parallelogram.
Thus, ABCD is a parallelogram, opposite sides of a parallelogram are congruent.
⇒ AB ≅ DC
⇒ BC ≅ BC (Reflexive Property of Congruence)
Hence, ∠ABC and ∠DCB are right angles by the definition of rectangle.
∠ABC ≅ ∠DCB (all right angles are congruent)
Therefore, by SAS property, ABC ≅ DCB.
⇒ segment AC ≅ segment BD
Learn more about rectangular congruency here:
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I need points soo I can post my question an get help my self...
Let the constant of variation be c.
We are given that y varies inversely with 2.5x, this means that:
y = (c) / (2.5x)
This can be written as:
2.5xy = c
Now, we a re given that y = 5.6 at x = 30.
Substitute with these values in the equation to get the value of c as follows:
2.5xy = c
2.5(30)(5.6) = c
c = 420
Therefore, the equation that describes the relation is:
2.5xy = 420
The value is 1.1. Because it is 1.1 spaces away. the negative symbol isn’t,t important in this case.
there is no question attached