Answer:
The slope intercept form is y=1/6x+1
Step-by-step explanation:
He would have $333 dollars in his account after all the checks and deposits.
(600+225)-(134+56+302)
(Deposits-checks)
Answer:
Helen’s net is correct because she reorganized the solid as a triangular prism.
This is because the net has a rectangular base and 4 triangular sides.
Step-by-step explanation:
Rectangular SA one side+1 = 30 x 9 = 270 + 1s= 270 x 2 =540sq^2
Rectangular side one side +1 = 18 x 9 = 162 +1s = 162 x 2 = 324sq^2
2 x 2 triangular sides either end = 4/3 x 15 x 27.3 + 18 x 30.9 = 409.5 (x2) = 819sq^2
=864 + 360
Pyramid area = 1236.71sq^2
Volume = V=1620^3
First, let's find the time where the ship arrives to point C
t=d/V, t= 45/30=1.5h
if the ship's departure time is at 1.5h, on the point C, let 's find its arrival to the point O, V=D/Dt, Dt=tfinal-tinitial
Dt=D/V= 20/30=0.6h=t final -t initial, implies t final=0.6+t initial=0.6+1.5=2.1h
so the ship will be on the radar at 2.1h,
