The answer is C 20s3+ 10s2+ 32s+ 6
Two times four
Eight divide in half
Eight
Six times four
Twenty four
Eight plus twenty four
Thirty two
When you have a triangle just multiply the sides then divide that total by half that will be the area for that
The answer is 12+3r because 4 times 3=12 then the 3r which you cannot add because they are no others variables that are r
Answer: " m = zC / (C − z) " .
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Explanation:
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Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
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Wouldn’t you just for part a, insert different x values and solve to get your y value. and do that over and over again with different numbers to create a data table. and then for part b you’ll just make a graph and put down the points. so for the first slot, do 0 for x. y will equal -1 after solving, so your first plot for part b can be (0,-1) and continue on from there
