All categories

3 years ago

What is the domain of f(x) = 37x?

Mathematics

2 answers:

8_murik_8 [283]3 years ago

8 0

All real numbers! All domains of monomials are all real numbers

ollegr [7]3 years ago

3 0

Answer:all real numbers

Step-by-step explanation:

You might be interested in

Write the following number in standard form 7.21x10^5

Ulleksa [173]

Answer:

721000

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What does rate of change mean

jeka94

Answer:

A rate of change is a rate that describes how one quantity changes in relation to another quantity.

8 0

4 years ago

Jaclyn estimates that the square root of 50 in the following way: √50 = 2√25 = 2*5 = 10

Harman [31]

Answer:

Jacklyn is wrong because

$\sqrt{50} \ne2 \sqrt{25 }$

Step-by-step explanation:

We have that :Jaclyn estimates that the square root of 50 in the following way:

$\sqrt{50} = 2 \sqrt{25}$

$\sqrt{50} = 2 \times 5$

$\sqrt{50} = 10$

Jacklyn is wrong because she made an error at

$\sqrt{50} = 2 \sqrt{25}$

The correct expression is

$\sqrt{50} = \sqrt{2 \times 25}$

This gives:

$\sqrt{50} = \sqrt{ 25} \times \sqrt{2}$

$\sqrt{50} =5 \sqrt{2}$

8 0

3 years ago

What is the perimeter of quadrilateral ABCD with verticals at A(-11,-6) b(-3,0) c(1,0) and d (1,-6)

dedylja [7]

<u>Answer:</u>

32 units

<u>Step-by-step explanation:</u>

We have a quadrilateral ABCD and we are given the following coordinates for these vertices:

A (-11,-6)

B (-3,0)

C (1,0)

D (1,-6)

AB = $\sqrt{(0-(-6))^2+(-3-(-11)^2} = \sqrt{36+64} =\sqrt{100}$ = 10 units

BC = $\sqrt{(0-0)^2+(1-(-3)^2} = \sqrt{0+16} =\sqrt{16}$ = 4 units

CD = $\sqrt{(0-(-6))^2+(1-1^2} = \sqrt{36+0} =\sqrt{36}$ = 6 units

AD = $\sqrt{(-6-(-6))^2+(1-(-11)^2} = \sqrt{0+144} =\sqrt{144}$ = 12 units

Perimeter of ABCD = $10+4+6+12$ = 32 units

6 0

3 years ago

WILL GIVE BRAINLIEST

-BARSIC- [3]

Answer:

it is C

Step-by-step explanation:

because i had this problem and i got it right

4 0

3 years ago

Read 2 more answers