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3 years ago

Use the discriminant to describe the roots of each equation. Then select the best description.

Mathematics

1 answer:

Reil [10]3 years ago

8 0

D = b^2 - 4ac = 7^2 - 4*2*6 = 49 - 48 = 1 So there are 2 roots and

the roots are real and rational

b

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there are 14 girls trying out for volleyball. Each team will have six players. How many four teams will be made?

nikdorinn [45]

Answer:

Step-by-step explanation:

14 divided by 6 = 2.33333333

only 6 in a group so you round it

and you get 2

3 0

3 years ago

Lori creates the following design for a T-shirt.

kakasveta [241]

Solution-

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7

Area of rectangle 1 = 8.68 sq.in

$\Rightarrow FH \times HI=8.68$

$\Rightarrow EB \times HI=8.68$ (∵ sides of the rectangle 2)

$\Rightarrow 2.8 \times HI=8.68$

$\Rightarrow HI=3.1$

Area of Triangle 1 = 6.48 sq.in

$\Rightarrow \frac{1}{2}\times AE \times EG= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48$

$\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48$ (∵ sides of the rectangle 1)

$\Rightarrow EF+3.1= 5.4$

$\Rightarrow EF=2.3$

$\Rightarrow BH=2.3$ (∵ sides of the rectangle 2)

$BC = BH+HI+IC$

$\Rightarrow 11.7= 2.3+3.1+IC$

$\Rightarrow IC=6.3$

The area of Rectangle 2,

$=EB\times BH =2.8\times 2.3=6.44\ sq.in$

The area of Triangle 2,

$\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in$

The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in

6 0

3 years ago

How do I solve the equation? -34= v+42-5v

Alex17521 [72]

-34=v+42-5v
-76=-4v
V= 19

8 0

3 years ago

Read 2 more answers

20 plus 30 is 50 is rhis stament correct or incorrect.

Sunny_sXe [5.5K]

Answer:

It is correct

Step-by-step explanation:

20 + 30 = 50

6 0

2 years ago

Read 2 more answers

A man 6ft tall walks at a rate of 6ft/s away from a lamppost that is 23 ft high. At what rate is the length of his shadow changi

Alekssandra [29.7K]

Suppose,
x = distance of the man
s = length of the shadow

Using the idea of similar triangles

6/s = 23/(x + s) 

Simplifying:
we get,
6(x + s) = 23s 

6x + 6s = 23s 

6x = 17s 

Differentiating with respect to time, 

6(dx/dt) = 17(ds/dt) 

Manipulating the above equation for ds/dt,

ds/dt = (17/6)(dx/dt) 

ds/dt = (17/6)(6) 

ds/dt = 17 ft/sec.

6 0

2 years ago