Endocrine system im pretty sure
Answer is: B) titration.
Equivalence point is the point in which there is stoichiometrically equivalent amounts of acid and base.
Chemist can draw pH curve (graph showing the change in pH of a solution, which is being titrated) for titration and determine equivalence point.
The midpoint of a steep vertical section indicates the equivalence point
Answer:
a) Xbenzene = 0.283
b) Xtoluene = 0.717
Explanation:
At T = 20°C:
⇒ vapor pressure of benzene (P*b) = 75 torr
⇒ vapor pressure toluene (P*t) = 22 torr
Raoult's law:
∴ Pi: partial pressure of i
∴ Xi: mole fraction
∴ P*i: vapor pressure at T
a) solution: benzene (b) + toluene (t)
∴ Psln = 37 torr; at T=20°C
⇒ Psln = Pb + Pt
∴ Pb = (Xb)*(P*b)
∴ Pt = (Xt)*(P*t)
∴ Xb + Xt = 1
⇒ Psln = 37 torr = (Xb)(75 torr) + (1 - Xb)(22 torr)
⇒ 37 torr - 22 torr = (75 torr)Xb - (22 torr)Xb
⇒ 15 torr = 53 torrXb
⇒ Xb = 15 torr / 53 torr
⇒ Xb = 0.283
b) Xb + Xt = 1
⇒ Xt = 1 - Xb
⇒ Xt = 1 - 0.283
⇒ Xt = 0.717
The approximate degree of dissociation of a 0.35 M solution of lactic acid is 4,87%
<h3>What is degree of dissociation?</h3>
The degree of dissociation is the quantity used to express the strength of a base, that is, its ability to conduct electric current, which depends on the amount of ions released in the dissociation.
The degree of dissociation (α) is another way of determining the strength of a base. It indicates the fatty acids that were released from a base when it dissociates in water.
With that being said, C stands for concentration and α is the the degree of dissociation.
Latic Acid can be written as C3H6O3
![Ka = \frac{[H^{+}] [CH3CH(OH)CO2^{-}] }{CH#CH(OH)CO2H} = \frac{C^{2} \alpha^{2} }{C(1-\alpha )} = \frac{C\alpha ^{2} }{(1-\alpha )}](https://tex.z-dn.net/?f=Ka%20%3D%20%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%20%5BCH3CH%28OH%29CO2%5E%7B-%7D%5D%20%20%7D%7BCH%23CH%28OH%29CO2H%7D%20%3D%20%5Cfrac%7BC%5E%7B2%7D%20%5Calpha%5E%7B2%7D%20%20%7D%7BC%281-%5Calpha%20%29%7D%20%3D%20%5Cfrac%7BC%5Calpha%20%5E%7B2%7D%20%7D%7B%281-%5Calpha%20%29%7D)
As α is too small (1-α) can be neglected.
![Ka = C\alpha ^{2} \\\\\\alpha = \sqrt[]{\frac{Ka}{C} }](https://tex.z-dn.net/?f=Ka%20%3D%20C%5Calpha%20%5E%7B2%7D%20%20%5C%5C%5C%5C%5C%5Calpha%20%20%20%20%3D%20%5Csqrt%5B%5D%7B%5Cfrac%7BKa%7D%7BC%7D%20%7D)
In this case, is possible to see that approximate degree of dissociation of a 0.35 M solution of lactic acid is 4,87%
See more about pKa at: brainly.com/question/14924722
#SPJ1
Someone is watching so I'm not answer this question
