A single water molecule can form 4 Hydrogen Bonds.
A hydrogen atom that is linked to a highly electronegative atom and another highly electronegative atom that is close by interact with one another to form hydrogen bonds, which are an unique kind of attractive intermolecular interactions. This process is known as hydrogen bonding. Hydrogen, for instance, is covalently linked to the more electronegative oxygen atom in water molecules (H2O). Therefore, the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another H2O molecule are what cause hydrogen bonding to form in water molecules.
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The answer is six because it is in group six A on the periodic table.
Answer: Hydrogen belongs to group 1 metal elements in the periodic table.
Explanation:
The hydrogen is a highly active metal. It has a single electron in its valence shell and it can donate its electron to other metal atoms. Thus forming metal hydrides. The hydrogen when ignited it reacts with oxygen and burns explosively this is indicative of high reactivity and spontaneous reactivity of hydrogen atom.
Step 1: add electrons to fill the 1s subshell (maximum of 2 electrons), when this is full, go to step 2. Step 2: add electrons to fill the 2s subshell (maximum of 2 electrons), when this is full, go to step 3. Step 3: add electrons to fill the 2p subshell (maximum of 6 electrons), when this is full, go to step 4. Step 4: add electrons to fill the 3s subshell (maximum of 2 electrons), when this is full, go to step 5. Step 5: add electrons to fill the 3p subshell (maximum of 6 electrons), when this is full, go to step 6. Step 6: add electrons to the 4s subshell (maximum of 2 electrons), when this is full, go to step 7. Step 7: add electrons to the 3d subshell (maximum of 10 electrons), when this is full, go to step 8. Step 8: add electrons to the 4p subshell (maximum of 6 electrons), when this is full, go to step 9. etc
So for Cu would be: 1s^22s^22p^63s^23p^63d^9
Ag would be: 1s^22s^22p^63s^23p^63d^104s^24p^64d^105s^1
Au would be: 1s^22s^22p^63s^23p^63d^104s^24p^64d^105s^25p^64f^145d^106s^1
<h3>
Answer:</h3>
825 mL
<h3>
Explanation:</h3>
<u>We are given;</u>
- Molarity of HCl is 0.200 M
- Mass of CaCO₃ is 8.25 g
- The equation of the reaction as;
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
We are required to calculate the volume of the Acid that reacted.
<h3>Step 1: Determine the moles of CaCO₃ that reacted;</h3>
We know that;
Moles = Mass ÷ molar mass
Molar mass CaCO₃ is 100.1 g/mol
Therefore;
Moles of CaCO₃ = 8.25 g ÷ 100.1 g/mol
= 0.0824 moles
<h3>Step 2: Determine the moles of HCl that reacted;</h3>
From the reaction, 1 mole of CaCO₃ reacts with 2 moles of HCl
Therefore;
Moles of HCl = Moles of CaCO₃ × 2
= 0.0824 moles × 2
= 0.1648 moles
= 0.165 moles
<h3>Step 3: Determine the volume of HCl </h3>
We know that, Molarity = Moles ÷ Volume
Rearranging the formula;
Volume = Moles ÷ Molarity
Therefore;
Volume of HCl = 0.165 moles ÷ 0.200M
= 0.825 L
But, 1 L = 1000 mL
= 825 mL
Therefore, the volume of HCl that reacted with CaCO₃ 825 mL