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san4es73 [151]
4 years ago
6

Find the first, fourth, and eighth terms of the sequence. A(n)=-2*2^(x-1)

Mathematics
1 answer:
Anna007 [38]4 years ago
3 0
\bf \begin{array}{ccll}
n&term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&A(1)&-2(2)^{1-1}\\
&&-2(2)^0\\
&&-2\\\\
4&A(4)&-2(2)^{4-1}\\
&&-2(2)^3\\
&&-16\\\\
8&A(8)&-2(2)^{8-1}\\
&&-2(2)^7\\
&&-256
\end{array}
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