Question

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40°. Building A is 120 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet? Building A; it is around 100. 69 feet taller than building B Building A; it is around 50. 34 feet taller than building B Building B; it is around 100. 69 feet taller than building A Building B; it is around 50. 34 feet taller than building A.

Answer 1

Building A is 50 .34 ft taller than building B

The situation forms a right angle triangle.

Two right angle triangles are formed.

Right angle triangle:

Right angle triangle has one of its angle as 90 degrees.

Therefore, trigonometric ratios can be used to find the sides of the building.

The height of the buildings is the opposite sides of the triangle formed. The adjacent sides is the distance from the building to the person.

Therefore,

Building A;

• tan 40 = opposite / adjacent
• tan 40° = h / 120
• h = 100.691955741
• h = 100.69 feet

Building B:

• tan 40 = h / 60
• h = 50.3459778706
• h = 50.34 feet

Therefore, building A is around 50.34 ft taller than the building B

learn more on angle of elevation here: brainly.com/question/3105623