This would be Delores because it goes katy, Delores, Alex, Sam, Beth
So for example 11/3 is 3 2/3 because you divide 11 by 3 and how you do it is that 3 goes into 11 3 times so you would write three on top of the 11 and then subtract 11-9 which is 2 so it is 3 2/3
Answer:
5^12
Step-by-step explanation:
index notation rules states that when there is a power inside AND outside the brackets, they shall multiply together. hence, we will multiply 3 and 2 so we will get 6 and thus the answer will be 5^6. Sike, that's not the answer, we forgot to multiply 5 with that power too... so we will get 25^6 because same power (outside brackey) will affect everything inside...
now after we got 25^6, we need to simplify it to get 5^n ....
so as we know 5^2 is 25, we can do this,
(5^2)^6 so we will multiply the powers to get
5^12 which is your answer :)
pls mark this as brainliestttt
Answer:
g(-4) = -1
g(-1) = -1
g(1) = 3
Explanation:
If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.
For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.
Using the same idea as before g(-1) is g(x) when x = -1 so -1 will not be a solution because -1 is not less than -1 (< -1). -1 is not ≥ 2 either so we will be using the second equation because -1 is part of the interval -1≤x≤2 (it is a solution to this inequality), therefore -(x - 1)² + 3 will be used.
As x = -1, -(x - 1)² + 3 = -(-1 - 1)² + 3 = -(-2)² + 3 = -4 + 3 = -1.
It is a coincidence that g(-1) = -1.
Now for g(1), where g(x) has an input of 1 or the value of the function where x = 1, we will not use the first equation because x = 1 → x < -1 → 1 < -1 [this is false because 1 is never less than -1], so we will not use -1.
We will use -(x - 1)² + 3 again because 1 is not ≥ 2, 1≥2 [this is also false]. And -1 ≤ 1 < 2 [This is a true statement]. Therefore g(1) = -(1 - 1)² + 3 = -(0)² + 3 = 3
