Answer:
x=7
Step-by-step explanation:
m angle SAR = m angle SQR (angles lying in the same segment of a circle are always equal)
that's why
7x+7=9x-7
9x-7x= 7+7
2x= 14
x=7
In the smallest of the three triangles (with sides
) we have

In the second-largest triangle (with sides
), the length of the missing side is
. Then in the largest triangle (with sides
), we have



Equivalently, we have

In turn, we find

Answer:
Domain = 0≤m≤20 for mEZ+
Range = $100≤A≤$700 for all values of m
Step-by-step explanation:
Initial amount in the account = $100
Amount saved by beth monthly = $30
Amount in the bank after X month = $100+$30X where X is the number of months beth intend to save up to.
The amount in her bank in her first month = $100+$30(1)
= $100+$30
= $130
Amount saved in the second month will be when X = 2
= $100+$30(2)
= $100+$60
= $160
The amount in the bank will keep increasing by $30 monthly until the 20month.
The amount he will have in her bank in the 20th month will be at when X = 20
= $100+30X
= $100+30(20)
= $100+$600
= $700
This means that her money will be $130 in the first month and will keep increasing until it reaches $700 in the 20th month.
The DOMAIN will be the interval of the time she used in saving. Since she saved for 20months, the domain will be expressed as 0≤m≤20 for mEZ+ where m is the number of month she uses to save.
The Range will represent the amount she saved within the specified time and will be expressed as $100≤A≤$700 for all values of m.
Where $100 is the amount in the account initially and $700 is the amount in the account after 20 months.
I dont have time to do all of these right now my apolgies but Ill explain how to do it.
The 3 angles of a triangle add up to 180.
So let me show you how to do 1.
.
.
.
1. 58 degrees
92, 30, ?
If we add together the first two angles,
92+30= 122
Knowing the total addition of all three angles would ne 180, we can subtract 122 from it to get the third angle.
180-122= 58
So we now know the last angle is 58 degrees because
92+30+58=180
It is that the angle has to be formed by two pairs of congruent/corresponding sides of the triangle