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deff fn [24]
1 year ago
11

Jose bout 9 movie tickets for a total of $54 adult tickets cost $8 is an adult child ticket cost $3.50 each. How many adult tick

ets did he buy?
Mathematics
1 answer:
dlinn [17]1 year ago
8 0

We know that

• 9 tickets cost $54.

,

• Adult tickets cost $8.

,

• Child ticket costs $3.50.

Let's call <em>x</em> adult tickets and <em>y</em> child tickets.

Using the given information, we can define the following.

x+y=9

Because Jose bought 9 tickets in total.

Then, we express another equation.

8x+3.50y=54

This equation represents the costs.

Let's isolate <em>y</em> in the first equation.

y=9-x

Then, we replace this last expression in the second equation.

8x+3.50(9-x)=54

We solve for <em>x</em>.

\begin{gathered} 8x+31.50-3.50x=54 \\ 4.50x=54-31.50 \\ 4.50x=22.50 \\ x=\frac{22.50}{4.50} \\ x=5 \end{gathered}<h2>Therefore, Jose bought 5 adult tickets.</h2>

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