Question

Jose bout 9 movie tickets for a total of $54 adult tickets cost $8 is an adult child ticket cost $3.50 each. How many adult tickets did he buy?

Answer 1

We know that

• 9 tickets cost $54.

,

• Adult tickets cost $8.

,

• Child ticket costs $3.50.

Let's call x adult tickets and y child tickets.

Using the given information, we can define the following.

$x+y=9$

Because Jose bought 9 tickets in total.

Then, we express another equation.

$8x+3.50y=54$

This equation represents the costs.

Let's isolate y in the first equation.

$y=9-x$

Then, we replace this last expression in the second equation.

$8x+3.50(9-x)=54$

We solve for x.

$\begin{gathered} 8x+31.50-3.50x=54 \\ 4.50x=54-31.50 \\ 4.50x=22.50 \\ x=\frac{22.50}{4.50} \\ x=5 \end{gathered}$

Therefore, Jose bought 5 adult tickets.