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Korvikt [17]
3 years ago
8

Fraggles are mythical, mouselike creatures that live underground beneath a large vegetable garden. Of the 100 Fraggles in this p

opulation, 84 have green fur and 16 have gray fur. A dominant allele F confers green fur, and a recessive allele f confers gray fur. Assuming Hardy–Weinberg equilibrium is operating, answer the following questions. (a) What is the frequency of the gray allele f? (b) What is the frequency of the green allele F? (c) How many Fraggles are heterozygotes (Ff)? (d) How many Fraggles are homozygous recessive (ff)? (e) How many Fraggles are homozygous dominant (FF)?
Biology
1 answer:
Triss [41]3 years ago
6 0

Answer:

a) 0.4

b) 0.6

c) 0.48

d) 0.16

e) 0.36

Explanation:

It is given that  alleles for confers green fur (F) are dominant over allele for confers gray fur (f)

Given , out of 100 fraggles, 16 have gray furs.

Gray fur allele is recessive. Thus,  genotype for a recessive fraggle would be "ff", hence its frequency would be

\frac{16}{100} \\= 0.16

q^{2} = 0.16\\

a)

Thus, allele for recessive fraggle would be represented by "q" and it is equal to \sqrt{0.16} \\= 0.4

b)

Allele for dominant allele would be represented by "p" and it is equal to

p= 1-q\\p= 1-0.4\\p=0.6

c) As per Hardy Weinberg's equation,

p^2+q^2+2pq = 1\\0.4^2 + 0.6^2 + 2pq = 1\\2pq = 1-0.16-0.36\\2pq = 0.48\\

d) Fraggles are homozygous recessive (ff) = 0.16

e) Fraggles are homozygous dominant (FF) = 0.36

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Further Explanation:

Succession involves small scale changes within a community that occur repeatedly over the life of that community.

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In the proto-solar system nebula, gravity pulled matter together to form larger bodies. As they collided, what happened to these
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A population is in Hardy-Weinberg Equilibrium with respect to a gene, "yellow," which has 2 alleles, y and Y. Y, the wild type a
Anton [14]

Answer:

The frequency of the Y allele is 0.7

The frequency of the y allele is 0.3

The frequency of the YY homozygote is 0.49

The frequency of the Yy heterozygote is 0.42

Explanation:

According to Hardy-Weinberg Equilibrium,

p + q = 1

p² + 2pq + q² = 1

where,

p = frequency of dominant allele

q = frequency of recessive allele

p² = frequency of dominant homozygous genotype

2pq = frequency of heterozygous genotype

q² = frequency of  recessive homozygous genotype

Here,

yy = q² = 0.09

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7 0
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