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natita [175]
4 years ago
12

How to write one fifth of the square of a number

Mathematics
1 answer:
labwork [276]4 years ago
4 0

\frac{1}{5}(whaever \: ur \: number \: is) {}^{2}

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Find the exact values of sin(u/2) cos(u/2) and tan(u/2) given sin u=24/25 and pie/2 < u < pie
vlada-n [284]

Recall the double/half angle formulas:

\cos^2\dfrac x2=\dfrac{1+\cos x}2

\sin^2\dfrac x2=\dfrac{1-\cos x}2

We're given \sin u=\frac{24}{25}, and since u is between π/2 and π, we expect \cos u to be negative. So from the Pythagorean identity, we find

\sin^2u+\cos^2u=1\implies\cos u=-\sqrt{1-\sin^2u}=-\dfrac7{25}

Also, we know \frac u2 will fall between π/4 and π/2, so both \sin\frac u2 and \cos\frac u2 will be positive. Then we find

\cos\dfrac u2=\sqrt{\dfrac{1+\cos u}2}=\dfrac35

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and it follows that

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4 years ago
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3 years ago
The population of a particular village can be modeled by the equation y=110x+56, where x is the number of years since 1990. In w
kkurt [141]

In this question, it is given that

The population of a particular village can be modeled by the equation

y=110x+56

where x is the number of years since 1990.

And we have to find in what year were there 1706 people living in the village?

So we put 1706 for y and solve for x. That is

1706=110x+56

Subtracting 56 from both sides.

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x= 15

And 1990 +15=2005

Therefore in 2005, there were 1706 people living in the village


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3 years ago
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1. How many Grade 10C students should join so that they can fill the quota? (Show your computation).​
expeople1 [14]
You have to put the b is
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