Compare the square of the side length of the largest side with the sum of the squares of the other two sides.:
AC^2 = 100 BC^2 = 86 AB^2 = 20
BC^2 + AB^2 = 86 + 20 = 106
100 < 106 => AC^2 < BC^2 + AB^2 =>
all the angles are less than 90°, which means the triangle is actue.
That is becasue when the square of the largest side is equal to the sum of the squares of the smaller sides, there is a right angle and the triangle is a right triangle (Pytaghorean theorem). When the square of the largest side is less than the sum of the squares of the other two sides, the angle is less than 90°, and the triangle is acute.
2) Which set represents the side lengths of a right trianle?
3) Which property disproves the statement in the student's notes?
Answer: option B) all angles of a rhombus are not congruent.
Explanation:
A rhombus is a quadrilateral whose four sides all have the same length. It is a quadrilateral.
The angles do not need to be congruent. Only the square, which is only one special case of rhombus, has the four angles congruent, but the masure of the angles of other rhombus are not equal.
4) What is the are of the figure?
Answer: 85 unit^2
Explanation:
1) Area of the rectangle = base * height = 4 * 9 = 36 2) area of the trapezoid = height * half of the sum of the bases = 7 * (3+7)/2 = 35 3) area of the rhombus = half the product of the diagonals = 7 * 4 / 2 = 14
Result: 36 + 35 + 14 = 85
That option is not among the choices. The nearest one is 84 unit^2.
Page 2 is the same page 1.
Page 3:
5) Question 8:
What line can be used to draw the altitude of the triangle FGH
Answer: option D: 3y = 7x + 16
Explanation:
1) All triangles have 3 altitudes (one for each vertex).
2) Now I am going to find the altitude of the vertex H (respect to base FG.
3) First calculate the slope of the segment FG:
slope = [y2 - y1] / [x2 - x1]
x2, y2 are the coordinates of the point G (6, -2) and x1, y1 are the coordinates of the point F (-8,4)