De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
Answer:
? = 125°
Step-by-step explanation:
The central angle is equal to the measure of the arc that subtends it, thus
? = 125°
Answer:
As far as i can tell it would just be y+2?
Well first set up the first ratio as 6/24. That is commercial mins over show time mins. Then to keep the units the same convert 2 hours into minutes which would be 120 minutes. Then set up your next ratio as x/120 since you’re trying to find the commercial minutes. Then cross multiply so that it’s 24x=720 and then x=30 and that’s the amount of commercial minutes for 2 hours.
Answer:
I suppose you're trying to make a triangle of some sort on a plane! So, in this case, yes the three points would reside all on the same plane. Making all three of them collinear.
