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3 years ago

If a rectangle measures 21 centimeters by 28 centimeters what is the length in centimeters of the diagonal of the rectangle

Mathematics

1 answer:

SOVA2 [1]3 years ago

4 0

Answer:

35cm

Step-by-step explanation:

Given data

Length= 21cm

Width= 28cm

Diagonal= ???

Applying Pythagoras theorem

D^2= L^2+W^2

D^2= 21^2+28^2

D^2= 441+784

D^2= 1225

D= √1225

D= 35cm

Hence the diagonal is 35cm

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Given that two points are (0, 2) and (6, 4)

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The midpoint of line joining two points is given as:

For a line containing two points $(x_1, y_1)$ and $(x_2, y_2)$

$\text {Midpoint}(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

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$x_{1}=0 ; y_{1}=2 ; x_{2}=6 ; y_{2}=4$

Substituting the values in given formula,

$\begin{array}{l}{\text {Midpoint}(x, y)=\left(\frac{0+6}{2}, \frac{2+4}{2}\right)} \\\\ {\text {Midpoint }(x, y)=\left(\frac{6}{2}, \frac{6}{2}\right)=(3,3)}\end{array}$

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