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professor190 [17]

3 years ago

7

Caleb's monthly bank statement showed the following deposits and withdrawals:

1 answer:

Crazy boy [7]3 years ago

6 0

Answer:

$174.72

Step-by-step explanation:

105.88+43.50+36.61+92.78-38.19-65.86=174.72

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Find the slope of the graph

zhuklara [117]

Answer:

Slope = $\frac{3}{2}$

Step-by-step explanation:

Slope = $\frac{6}{4} =\frac{3}{2}$

4 0

3 years ago

PLEASE HELP ME!! 1.02: Triangle Similarity 1<br><br> What is the value of X?

hichkok12 [17]

Answer:

<h2>x = 28</h2>

Step-by-step explanation:

ΔARP and ΔCRD are similar. Therefore the sides are in proportion:

$\dfrac{AR}{CR}=\dfrac{PR}{DR}$

We have:

AR = 10 + x

CR = x

PR = 15 + 42 = 57

DR = 42

Substitute:

$\dfrac{10+x}{x}=\dfrac{57}{42}$ <em>cross multiply</em>

$42(10+x)=57x$ <em>use distributive property</em>

$(42)(10)+(42)(x)=57x$

$420+42x=57x$ <em>subtract 42x from both sides</em>

$420=15x$ <em>divide both sides by 15</em>

$x=28$

6 0

3 years ago

Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join

zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx = 1$

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y) and replacing a and b with their respective values, we have

$\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx = 1$

Since c is a constant, we can bring it out of the integral sign; to give us

$c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx = 1$

Open the bracket

$c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx = 1$

Integrate with respect to y

$c\int\limits^3_0 {\frac{xy^{2}}{2} +\frac{xy^{3}}{3} } \, dx (0,3}) = 1$

Substitute 0 and 3 for y

$c\int\limits^3_0 {(\frac{x* 3^{2}}{2} +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2} +\frac{x * 0^{3}}{3})} \, dx = 1$

$c\int\limits^3_0 {(\frac{x* 9}{2} +\frac{x * 27}{3} ) - (0 +0) \, dx = 1$

$c\int\limits^3_0 {(\frac{9x}{2} +\frac{27x}{3} ) \, dx = 1$

Add fraction

$c\int\limits^3_0 {(\frac{27x + 54x}{6}) \, dx = 1$

$c\int\limits^3_0 {\frac{81x}{6} \, dx = 1$

Rewrite;

$c\int\limits^3_0 (81x * \frac{1}{6}) \, dx = 1$

The $\frac{1}{6}$ is a constant, so it can be removed from the integral sign to give

$c * \frac{1}{6}\int\limits^3_0 (81x ) \, dx = 1$

$\frac{c}{6}\int\limits^3_0 (81x ) \, dx = 1$

Integrate with respect to x

$\frac{c}{6} * \frac{81x^{2}}{2} (0,3) = 1$

Substitute 0 and 3 for x

$\frac{c}{6} * \frac{81 * 3^{2} - 81 * 0^{2}}{2} = 1$

$\frac{c}{6} * \frac{81 * 9 - 0}{2} = 1$

$\frac{c}{6} * \frac{729}{2} = 1$

$\frac{729c}{12} = 1$

Multiply both sides by $\frac{12}{729}$

$c = \frac{12}{729}$

$c = 0.0165 (Approximately)$

8 0

3 years ago

All of the following proportions are equivalent except

shtirl [24]

All are equal except A/D = C/B

I replaced the values with numbers
a=5 b=10 c=50 d=100

10/5=100/50 so it’s not b/a = d/c
5/10=50/100 so it’s not a/b = c/d
5/50 = 10/100 so it’s not a/c = b/d
5/100 is NOT 50/10 so it’s NOT a/d = c/b

8 0

3 years ago

Which inequality does not belong with the other three? Explain your reasoning.

ra1l [238]

The correct answer is 3/4

4 0

3 years ago