I need help on 4,5,6,7,8,9 asappppp

Bob has a recipe for salad dressing. The recipe says to mix 14 c lemon juice, 18 c mustard, and 14 c vinegar. How much lemon jui

Alex73 [517]

Answer:

He needs 56c of lemon juice to make 4 salad dressings.

Step-by-step explanation:

We only need to look at how much lemon juice to make one salad dressing which would be 14c so we have to make 4 so we would do 14x4 to get how much lemon juice you need to make 4 dressings so you would need 56c of lemon juice to make 4 dressings

7 0

3 years ago

Read 2 more answers

10 to the 5th power plus 10 to the -1 power

Serggg [28]

1000000+1/10. There are no rules for when you add the powers.

8 0

4 years ago

PLEASE ANSWER ASAP!!! THANK YOU!!! ONLY 3 QUESTIONS!!

d1i1m1o1n [39]

For the each of them simply substitute for x in each equation to see if you get the corresponding y , it doesnt really get any more straightforward than this

4 0

3 years ago

Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I

xxTIMURxx [149]

Answer:

$t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971$

$p_v =2*P(t_{(1699)}>1.971)=0.049$

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=669$ represent the sample mean

$s=732$ represent the sample standard deviation

$n=1700$ sample size

$\mu_o =68$ represent the value that we want to test

$\alpha=0.$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:

Null hypothesis: $\mu = 634$

Alternative hypothesis: $\mu \neq 634$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=1700-1=1699$

Since is a two sided test the p value would be:

$p_v =2*P(t_{(1699)}>1.971)=0.049$

Conclusion

If we compare the p value and the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

3 0

3 years ago

In Val's class, the ratio of students who ate enchiladas for lunch to the students who ate tacos was 14:20. Which of the followi

fgiga [73]

An equivalent ratio would be 7:10 or 70:100 or 42:60 and so on...

6 0

3 years ago