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sweet [91]
3 years ago
10

Can somone help me with this 1 problem? QRST is a parallelogram. Determine the measure of ∠Q

Mathematics
1 answer:
valina [46]3 years ago
3 0
(In the picture, QRST looks like a rhombus, so I will assume that it is a rhombus.)

In a rhombus, opposite angles are congruent based on the alternate interior angle theorem. In other words, R and T along with Q and S are both alternate interior angle pairs.
(You can actually test this by printing out a rhombus, cutting out the angles, and matching up the opposite ones.) 

We know that Q is equal to 4x + 10, but we need to solve for x. Since Q and S are congruent, we can set them equal to each other:
1) 4x + 10 = 5x - 3
2) 4x + 13 = 5x
3) 5x = 4x + 13
4) x = 13
Now let's plug 13 in for Q:
5) 4(13) + 10 = 52+10 = 62

I got m<Q = 62 degrees. Hope this helps!
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If a seed is planted, it has a 80% chance of growing into a healthy plant.
AlladinOne [14]

Answer:

0.336

Step-by-step explanation:

Use binomial probability:

P = nCr p^r q^(n-r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Here, n = 8, r = 7, p = 0.8, and q = 0.2.

P = ₈C₇ (0.8)⁷ (0.2)⁸⁻⁷

P = 0.336

3 0
3 years ago
Given that a function, h, has a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25 and that h(8) = 19 and h(-2) = 2, select the
AveGali [126]

The true statement is h(2)=16.

<h3 /><h3>What is domain and range?</h3>

The domain of a function is the set of values that we are allowed to plug into our function. The range of a function is the set of values that the function assumes.

Given:

domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25,

Also, h(8) = 19 and h(-2) = 2,

Now,

2=h(-2)< h(2)<h(8) =19

h(8)=19≠21

h(13)> h(8) =19

h(-3)< h(-2) =2  [1 ≤ h(x) ≤ 25]

Hence, h(2)=16

Learn more about domain and range:

brainly.com/question/23199615

#SPJ1

5 0
2 years ago
5. Write down the nth term of each of the following G.Ps
yawa3891 [41]

Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

ii) Eight term = -1/1594323

Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

7 0
3 years ago
What is a segment bisector
ruslelena [56]

A segment bisector is a segment, ray, line, or plane that intersects a given segment at its midpoint.

For example, in the diagram shown, line SQ bisects segment PR because line SQ intersects segment PR at its midpoint which is Q.

7 0
3 years ago
Hellp guys I need good help
LUCKY_DIMON [66]

Answer:

1.B 2.D 3.C 4.A

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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