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Veseljchak [2.6K]
3 years ago
10

A bag contains five red marbles, two orange marbles, one yellow marble, and two green marbles. Two marbles are drawn from the ba

g.
What is the approximate probability of choosing an orange marble and a green marble?

0.02222
0.04444
0.08889
0.13333
Mathematics
2 answers:
Katen [24]3 years ago
7 0

Answer:

b

Step-by-step explanation:

Anvisha [2.4K]3 years ago
4 0
The answer is

\frac{2}{10}  \div  \frac{2}{9}  = .04444
the probability of choosing an orange marble is 2/10 because there are 2 orange marbles and 10 marbles in total.

the probability of choosing a green marble is 2/9 because there are 2 green marbles and 9 marbles in total (because you already picked one marble out of the bag thereby decreasing the total number of marbles in all).

when you multiply the probability of these two events you get .04444 which is the probability of both events happening simultaneously.
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The answer is b because
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A manager asked her employees how many times they had given blood in the last year. The results of the survey are given below. T
stira [4]

<u>Complete Question</u>

The probability distribution table is given below:

\left|\begin{array}{c|ccccccc}x&0&1&2&3&4&5&6\\P(x) &0.33 &0.24& 0.16& 0.12 &0.08 &0.05& 0.02\end{array}\right|

Answer:

1.61

Step-by-step explanation:

The probability distribution table is given below:

\left|\begin{array}{c|ccccccc}x&0&1&2&3&4&5&6\\P(x) &0.33 &0.24& 0.16& 0.12 &0.08 &0.05& 0.02\end{array}\right|

We want to determine the mean number of times a person gave blood.

Expected Value, E(x)=\sum x_i\cdot P(x_i)

=(0 \times 0.33)+ (1 \times 0.24)+(2\times0.16)+(3\times0.12)+(4\times0.08)+(5\times0.05)+(6\times0.02)\\=0+0.24+0.32+0.36+0.32+0.25+0.12\\=1.61\\

The mean number of times a person gave blood based on this survey is 1.61.

4 0
4 years ago
What’s the correct answer for this?
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Answer:

Step-by-step explanation: A

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3 years ago
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Answer:

Step-by-step explanation:

1) A similar triangle must have the same ratios of sides. Triangle ABC and triangle LNM are similar because all the sides of LNM are 1/2 of the sides of ABC. As they are all in a 1:2 ratio, the triangles are similar.

2) ADE and ABC are similar because each angle is the same. Angle D and Angle B are the same because they are shown as the same with the same dot symbolization. Angle E and C are the same because they are shown as the same with the same curvy angle representation. ADE and ABC share A as the same angle, so all three angles are the same.

5) As triangles ABC and EDC are similar, the sides must have the same ratio. ED is similar to AB, EC is similar to AC, and CD and BC are similar. First we find the ratio. The only pair of similar lines are EC and AC, so we have to find the ratio from those two lines. EC is 15 and AC is 10/3, so we do 15 divided by 10/3 and we get 9/2. Therefore, the ratio is 9/2. Now we can find x and y. We can first look at ED and AB. Ed is 12 and AB is y. We know that it must have the same ratio of 9/2, so 12/y must equal 9/2. We can do proportions. 12/y = 9/2, 9y = 24 (you multiply the numbers diagonally). So, we get y = 8/3. Now we can get x the same way. BC and CD are similar, and so x/5 must equal 9/2 as well. We use proportions again and we have x/5 = 9/2, so 45 = 2x and x = 45/2.

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3 years ago
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